写一个函数def add(request):获取Kipling表里面name的所有字段,封装到list里面
时间: 2023-03-10 10:39:45 浏览: 80
def add(request):
kipling_list = []
with request.cursor() as cursor:
sql = "SELECT name FROM Kipling"
cursor.execute(sql)
result = cursor.fetchall()
for row in result:
kipling_list.append(row[0])
return kipling_list