使用队列编程解决舞伴问题。

舞伴问题是指一群男女参加舞会，每个人都想找到一位异性舞伴，如果男女数量不匹配，则有些人可能无法找到舞伴。使用队列编程可以很好地解决这个问题。

具体实现方法如下：

1. 分别创建一个男生队列和女生队列，将所有男生和女生分别加入对应的队列中。

2. 每次从男生队列和女生队列中取出一个男生和一个女生，让他们成为舞伴。

3. 如果男生队列或女生队列为空，则停止匹配，剩余的人无法找到舞伴。

代码示例：

class DancePartnerQueue:
    def __init__(self):
        self.male_queue = []
        self.female_queue = []

    def add_male(self, name):
        self.male_queue.append(name)

    def add_female(self, name):
        self.female_queue.append(name)

    def match(self):
        while len(self.male_queue) > 0 and len(self.female_queue) > 0:
            male = self.male_queue.pop(0)
            female = self.female_queue.pop(0)
            print(f"{male} and {female} are dancing partners.")

        if len(self.male_queue) > 0:
            print(f"The following male(s) could not find a dance partner: {self.male_queue}")
        elif len(self.female_queue) > 0:
            print(f"The following female(s) could not find a dance partner: {self.female_queue}")
        else:
            print("Everyone has found a dance partner.")

使用示例：

dancers = DancePartnerQueue()

dancers.add_male("Adam")
dancers.add_male("Bob")
dancers.add_male("Charlie")

dancers.add_female("Alice")
dancers.add_female("Betty")
dancers.add_female("Cindy")
dancers.add_female("Diana")

dancers.match()

输出结果：

Adam and Alice are dancing partners.
Bob and Betty are dancing partners.
Charlie and Cindy are dancing partners.
The following female(s) could not find a dance partner: ['Diana']