已知稀疏矩阵A和B，编程代码实现基于三元组顺序表实现A+B的运算

以下是基于三元组顺序表实现稀疏矩阵A+B的Python代码：

class SparseMatrix:
    def __init__(self, numRows, numCols, triplets):
        self.numRows = numRows
        self.numCols = numCols
        self.triplets = triplets
        
    def __add__(self, other):
        if self.numRows != other.numRows or self.numCols != other.numCols:
            raise ValueError("Matrices have different shapes")
        
        i, j, k = 0, 0, 0
        result_triplets = []
        
        while i < len(self.triplets) and j < len(other.triplets):
            if self.triplets[i][0] < other.triplets[j][0] or \
            (self.triplets[i][0] == other.triplets[j][0] and self.triplets[i][1] < other.triplets[j][1]):
                result_triplets.append(self.triplets[i])
                i += 1
            elif self.triplets[i][0] > other.triplets[j][0] or \
            (self.triplets[i][0] == other.triplets[j][0] and self.triplets[i][1] > other.triplets[j][1]):
                result_triplets.append(other.triplets[j])
                j += 1
            else:
                result_triplets.append((self.triplets[i][0], self.triplets[i][1], self.triplets[i][2] + other.triplets[j][2]))
                i += 1
                j += 1
        
        while i < len(self.triplets):
            result_triplets.append(self.triplets[i])
            i += 1
        
        while j < len(other.triplets):
            result_triplets.append(other.triplets[j])
            j += 1
        
        return SparseMatrix(self.numRows, self.numCols, result_triplets)

其中，类SparseMatrix表示稀疏矩阵，triplets是三元组列表，每个元素是一个三元组(i, j, value)，表示在(i, j)位置上的值为value。__add__方法实现了两个稀疏矩阵相加的操作。具体实现过程为，遍历两个矩阵的三元组列表，按照行列坐标的大小关系进行合并，如果行列坐标相同，则将两个值相加。最后，将合并后的三元组列表构造成新的稀疏矩阵返回。

可以使用以下代码进行测试：

a = SparseMatrix(3, 3, [(0, 0, 1), (1, 1, 2)])
b = SparseMatrix(3, 3, [(0, 1, 3), (2, 2, 4)])
c = a + b
print(c.triplets)  # [(0, 0, 1), (0, 1, 3), (1, 1, 2), (2, 2, 4)]