TypeError: list.append() takes exactly one argument (4 given)
时间: 2023-09-10 07:15:08 浏览: 248
这个错误提示意味着您尝试在列表中使用 append() 方法时给了多个参数。请检查您的代码并确保在 append() 方法中只传递一个参数。例如,以下代码会导致类似的 TypeError:
```
my_list = []
my_list.append(1, 2, 3, 4)
```
而正确的写法应该是:
```
my_list = []
my_list.append(1)
my_list.append(2)
my_list.append(3)
my_list.append(4)
```
相关问题
TypeError: list.append() takes exactly one argument (2 given)
这个错误的意思是,你在调用列表的 `append()` 方法时传入了两个参数,但是该方法只接受一个参数。
例如,下面的代码会产生这个错误:
```
my_list = [1, 2, 3]
my_list.append(4, 5)
```
要修复这个错误,你需要检查你的代码,确保只在调用 `append()` 方法时传入一个参数。
例如,你可以这样做:
```
my_list = [1, 2, 3]
my_list.append(4)
my_list.append(5)
```
TypeError: list.append() takes exactly one argument (3 given)
This error occurs when you try to pass more than one argument to the `append()` method of a list. The `append()` method only takes one argument, which is the item you want to add to the end of the list.
For example, if you have a list called `my_list` and you want to add the integers 1, 2, and 3 to the end of the list, you might try to do it like this:
```
my_list = []
my_list.append(1, 2, 3)
```
However, this will result in a `TypeError` because you are passing three arguments to the `append()` method instead of just one.
To fix this error, you need to call the `append()` method once for each item you want to add to the list:
```
my_list = []
my_list.append(1)
my_list.append(2)
my_list.append(3)
```
Now the integers 1, 2, and 3 will be added to the end of the `my_list` list, and you will not get a `TypeError`.
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