麻烦把这个代码的正确形式用python写出来:#include<stdio.h> int main() { int n,i ,target; printf("Input n:") scanf("%d",&n); int [n]; printf("Input the number") for(int i=0; i<n; i++) { scanf("%d",&[i]) } printf("Please input the number to find:"); scanf("%d",&target); bool found=false for(int j=0;j<n;j++) { if ([v]=target) { found=ture; break; } } if(found) { printf("Find it"); } else { peintf("Can't find it"); } return 0 }
时间: 2024-01-22 11:03:59 浏览: 26
以下是将该C++代码转换为Python的正确形式:
```
n = int(input("Input n:"))
arr = []
print("Input the number")
for i in range(n):
arr.append(int(input()))
target = int(input("Please input the number to find:"))
found = False
for j in range(n):
if arr[j] == target:
found = True
break
if found:
print("Find it")
else:
print("Can't find it")
```
请注意,Python的语法和C++有很大不同,需要适当调整代码结构和语法。
相关问题
把下列代码翻译成python:#include<stdio.h> void main(){ int a,i=1; a = (++i) + (++i); printf("%d",a);}
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解释这段代码#include<stdio.h> int main() { printf("Hello world!"); return 0; }
这段代码使用Python语言编写,主要功能是将一个字符串中的每个单词的首字母大写,并返回修改后的字符串。
具体实现方法是,首先将原字符串按照空格分割成一个单词列表,然后遍历列表中的每个单词,将其首字母大写,再将修改后的单词添加到一个新的列表中。最后,将新的列表中的单词用空格连接起来,形成修改后的字符串,并返回该字符串。
代码中使用了Python内置的字符串方法capitalize()来将单词的首字母大写,使用了列表推导式来简化代码。
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