module test; typedef struct packed { logic [9:-1][2:0] a; //REQ-EXT-10001, REQ-EXT-10004 } ST1; typedef struct { ST1 st1; logic [2:0] b; } ST2; typedef struct { logic [31:0] c; // ST3 definition missing } ST3; typedef struct { ST3 st3; ST2 st2_arr[3:0]; } ST4; initial begin ST2 st2; ST2 st2_1 = {3'b101, {ST1{10'b110}}, {ST1{20'b10101010101010}},{ST1{30'b1}}}; ST2 st2_2 = {3'b010, {ST1{10'b101}}, {ST1{20'b01010101010101}},{ST1{30'b0}}}; st2 = {3'b1, {ST1{10'b110}}, {ST1{20'b10101010101010}}, {ST1{30'b1}}}; $display("%p",st2); //CHECK-001:'{a:'h1}, st2:'{'a:'h1}, '{a:'h0},'{a:h1}}} $display("st2_1:%p", st2_1); //CHECK-002 $display("st2_2:%p", st2_2); //CHECK-003 end endmodule when compiled by vcs, it says following verilog source has syntax error: "sc_assignment_pattern_035.sv", 35:token is '{' ST2 st2_1={3'b101, {ST1{10'b110}},{ST1{20'b1010101010}},{ST1{30'b1}}}; how to fix this syntax error so that it can be compiled by vcs?
时间: 2023-11-01 13:25:12 浏览: 32
The syntax error in the verilog source is due to the use of the packed struct initialization syntax '{ST1{}}' inside another struct initialization. To fix this, we can use the 'repeat' operator to initialize the packed struct arrays as follows:
```
ST2 st2_1 = {3'b101, {}};
repeat (3) begin
st2_1.st1.a[2*(i+1)-1:2*i] = 10'b110;
end
repeat (5) begin
st2_1.st1.a[2*(i+4)+2:2*(i+4)-1] = 10'b1010;
end
repeat (10) begin
st2_1.st1.a[2*(i+9)+2:2*(i+9)-1] = 10'b101010;
end
st2_1.st1.a[31:30] = 2'b01;
```
Similarly, we can initialize the other struct 'st2_2' using the 'repeat' operator.
相关问题
module test; typedef struct packed { logic [9:-1][2:0] a; ///REQ-EXT-10001, REQ-EXT-10004 } ST1; typedef struct { ST1 st1; ST1 st2[2:0]; }ST2; initial begin ST2 st2; st2 = '{2'b01, '{3'b1, 3'b0, 12'b1}}; $display("%", st2); //CHECK-001:'{a:'h1}, st2:'{'a:'h1}, '{a:'h0},'{a:h1}}} end endmodule 我想根据拓展点对这段sverilog代码进行拓展,无论怎么变化都可以,你能帮我变换几种吗?越多越好,谢谢你啦
好的,我可以为您提供几种不同的拓展点,以帮助您更好地理解和使用sverilog代码。以下是一些可能的拓展点:
1. 在ST1结构中添加一个新的字段,名为b:
```
typedef struct packed {
logic [9:-1][2:0] a; ///REQ-EXT-10001, REQ-EXT-10004
logic [7:0] b; ///REQ-EXT-10005
} ST1;
```
2. 在ST2结构中添加一个新的字段,名为c,它是一个逻辑向量:
```
typedef struct {
ST1 st1;
ST1 st2[2:0];
logic [3:0] c; ///REQ-EXT-10006
} ST2;
```
3. 在ST2结构中添加一个新的字段,名为d,它是一个逻辑向量数组:
```
typedef struct {
ST1 st1;
ST1 st2[2:0];
logic [3:0][7:0] d; ///REQ-EXT-10007
} ST2;
```
4. 在ST1结构中添加一个新的字段,名为e,它是一个逻辑二维数组:
```
typedef struct packed {
logic [9:-1][2:0] a; ///REQ-EXT-10001, REQ-EXT-10004
logic [3:0][7:0] e; ///REQ-EXT-10008
} ST1;
```
5. 在ST2结构中添加一个新的字段,名为f,它是一个ST1类型的结构:
```
typedef struct {
ST1 st1;
ST1 st2[2:0];
ST1 f; ///REQ-EXT-10009
} ST2;
```
这些只是一些可能的拓展点,您可以根据您的具体需求添加任何类型的拓展点。
module test; typedef struct packed { logic [9:-1][2:0] a; //REQ-EXT-10001, REQ-EXT-10004 }ST1; typedef struct { ST1 st1; ST2 st2[2:0]; }ST2; initial begin ST2 st2; st2='{2'b01, '{3'b1, 3'b0, 12'b1}}; //REQ-EXT-10101 &display("%p", st2); //CHECK-001: '{st1:'{a:'h1}, st2:"{'{a:'h1},'{a:'h0},'{a:'h1}}} end endmodule REQ-EXT-10101处可以如何修改,使得代码仍然可以跑通呢?
在 REQ-EXT-10101 处,可以将赋值语句修改为以下两种方式之一:
1. 使用大括号初始化整个结构体:
```verilog
st2 = '{ {10'h1}, '{3'b1, 3'b0, 12'h1} };
```
2. 逐个初始化结构体成员:
```verilog
st2.st1.a = '{10'h1};
st2.st2[0].a = '{3'b1, 3'b0, 12'h1};
st2.st2[1].a = '{3'b1, 3'b0, 12'h1};
st2.st2[2].a = '{3'b1, 3'b0, 12'h1};
```
修改后的完整代码如下:
```verilog
module test;
typedef struct packed {
logic [9:-1][2:0] a; //REQ-EXT-10001, REQ-EXT-10004
} ST1;
typedef struct {
ST1 st1;
ST2 st2[2:0];
} ST2;
initial begin
ST2 st2;
// 使用大括号初始化整个结构体
st2 = '{ {10'h1}, '{3'b1, 3'b0, 12'h1} };
$display("%p", st2); //CHECK-001: '{st1:'{a:'h1}, st2:"{'{a:'h1},'{a:'h0},'{a:'h1}}}
end
endmodule
```
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