for s in "abc": for i in range(3): print (s,end="") if s=="c": break用Python程序讲解
时间: 2023-11-30 18:05:18 浏览: 292
这是一个Python程序的循环嵌套示例,用于输出字符串“abc”三次。程序执行时,首先循环遍历字符串“abc”,然后在内部循环中输出该字符串的每个字符,并在最后一个字符时停止内部循环。
以下是Python代码的示例:
```
for s in "abc":
for i in range(3):
print(s, end="")
if s == "c":
break
```
程序输出结果为:
```
aaa
bbb
ccc
```
注意:作为AI语言模型,我的回答可能不是100%正确的,仅供参考。
相关问题
for s in "abc": for i in range(3): print (s,end="") if s=="c": break
The output of this code would be: "aaabbbccc"
Explanation:
The code consists of a nested loop. The outer loop iterates over each character in the string "abc". The inner loop iterates over the range of values from 0 to 2 (3 times) using the range() function.
During each iteration of the inner loop, the character from the outer loop is printed, using the print() function with the optional argument "end" set to an empty string to suppress the newline character.
When the character "c" is reached during the outer loop, the break statement is executed, which causes the inner loop to terminate immediately. However, the outer loop continues to iterate over the remaining characters in the string "abc", printing each character three times due to the completed inner loop.
for s in "abc": for i in range(3): print(s,end="") if s=="c": break 程序的输出结果和过程及原理
这段程序的输出结果为:abcabcabc。输出过程如下:
- 第一次循环:s = "a",i = 0,输出结果为 "a";
- 第二次循环:s = "a",i = 1,输出结果为 "a";
- 第三次循环:s = "a",i = 2,输出结果为 "a";
- 第四次循环:s = "b",i = 0,输出结果为 "b";
- 第五次循环:s = "b",i = 1,输出结果为 "b";
- 第六次循环:s = "b",i = 2,输出结果为 "b";
- 第七次循环:s = "c",i = 0,输出结果为 "c";
- 第八次循环:s = "c",i = 1,输出结果为 "c";
- 第九次循环:s = "c",i = 2,输出结果为 "c",然后由于满足条件 s=="c",执行 break 语句跳出循环。
该程序的原理是:外层循环遍历字符串 "abc",内层循环遍历数字 0、1、2,然后输出当前字符 s,输出三次后,如果当前字符为 "c",则跳出外层循环。因此最终输出结果为 "abcabcabc"。
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