输出一段python扫雷游戏代码

好的，以下是一个简单的 Python 扫雷游戏代码：

import random

def create_board(board_size, num_mines):
    board = [[0 for _ in range(board_size)] for _ in range(board_size)]
    mines = set()
    while len(mines) < num_mines:
        row = random.randint(0, board_size-1)
        col = random.randint(0, board_size-1)
        if (row, col) not in mines:
            mines.add((row, col))
            board[row][col] = '*'
            for r in range(row-1, row+2):
                for c in range(col-1, col+2):
                    if (0 <= r < board_size and 0 <= c < board_size and board[r][c] != '*'):
                        board[r][c] += 1
    return board

def print_board(board):
    board_size = len(board[0])
    for r in range(board_size):
        print(" ".join(str(board[r][c]) for c in range(board_size)))

def play_game(board_size=10, num_mines=10):
    board = create_board(board_size, num_mines)
    print_board(board)
    while True:
        row = int(input("Enter row: "))
        col = int(input("Enter col: "))
        if board[row][col] == '*':
            print("Game over!")
            return
        elif board[row][col] != 0:
            board[row][col] = str(board[row][col])
        else:
            # reveal adjacent squares
            reveal(board, row, col)
        print_board(board)

def reveal(board, row, col):
    board_size = len(board[0])
    if (0 <= row < board_size and 0 <= col < board_size and board[row][col] == 0):
        board[row][col] = ' '
        for r in range(row-1, row+2):
            for c in range(col-1, col+2):
                reveal(board, r, c)

play_game()

请注意，这只是一个基本的扫雷游戏，没有考虑复杂的规则或多个玩家等因素。