!RET & (!DFTRAMBYP | (TENA & QNAPA & CENA) | (TENA & TONAPA & TCENA)) & EMAA[2] & EMAA[1] & EMAA[0] & EMASA split this to sum of product form

To convert the given logical expression into a sum of products form, we need to follow these steps:

1. Apply De Morgan's law to eliminate the negation operator (!):

!RET AND (DFTRAMBYP OR (!TENA OR !QNAPA OR !CENA) OR (!TENA OR !TONAPA OR !TCENA)) AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA

2. Distribute the AND operator over the OR terms:

(!RET AND DFTRAMBYP AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !QNAPA AND !CENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !TONAPA AND !TCENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA)

3. Simplify each term by removing redundant variables:

(!RET AND DFTRAMBYP AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !QNAPA AND !CENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !TONAPA AND !TCENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA)

Therefore, the sum of products form of the given logical expression is:

(!RET AND DFTRAMBYP AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !QNAPA AND !CENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA) OR
(!RET AND !TENA AND !TONAPA AND !TCENA AND EMAA[2] AND EMAA[1] AND EMAA[0] AND EMASA)