Java中得getFiles

在Java中，可以使用以下代码获取指定目录下的所有文件：

import java.io.File;

public class GetFilesExample {
    public static void main(String[] args) {
        File directory = new File("path/to/directory");
        File[] files = directory.listFiles();
        for (File file : files) {
            if (file.isFile()) {
                System.out.println(file.getName());
            }
        }
    }
}

其中，`directory`表示要获取文件的目录，`listFiles()`方法返回一个`File`数组，包含目录中的所有文件和子目录。我们可以遍历这个数组并判断每个元素是否是一个文件，如果是文件则输出文件名。

相关问题

directory.GetFiles等价与Java中的啥

In Java, the equivalent of `Directory.GetFiles` would be the `File.listFiles()` method.

You can use it like this:

File folder = new File(saveAudioFolder);
File[] audioFiles = folder.listFiles();
for (File audioFile : audioFiles) {
    // do something with the audio file
}

This will return an array of `File` objects representing the files in the specified directory. You can then iterate over it to perform any required operations on the files.

Directory.GetFiles

Directory.GetFiles is a method in the .NET Framework that returns an array of file names in the specified directory that match the specified search pattern.

Syntax:

public static string[] GetFiles(string path, string searchPattern);

Parameters:
- path: the path to the directory to search
- searchPattern: the search pattern to match against the file names in the directory. This can include wildcards such as "*" and "?".

Return value:
- An array of file names that match the specified search pattern in the specified directory.

Example usage:

string[] files = Directory.GetFiles(@"C:\Users\Username\Documents", "*.txt");
foreach (string file in files)
{
    Console.WriteLine(file);
}

This code will search for all files with a .txt extension in the user's Documents folder and print out the file names.