需要用到Random随机类 nextInt()方法 质数是指在大于1的自然数中,除了1和它本身以外不再有其他因数的自然数。 还需要Collections.sort(list) 将数字从小到大排序
时间: 2024-01-22 13:17:28 浏览: 59
好的,我知道了。那么你需要一个程序,可以从用户输入的数字中找到最大的质数,并将输入的数字从小到大排序。你需要使用Random类的nextInt()方法来生成随机数字,然后检查这些数字是否为质数。最后,使用Collections.sort()方法对数字进行排序。
下面是一个示例程序,可以实现这个功能:
```java
import java.util.*;
public class PrimeNumberFinder {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
Random random = new Random();
System.out.print("请输入需要生成的数字个数:");
int count = scanner.nextInt();
List<Integer> numbers = new ArrayList<>();
for (int i = 0; i < count; i++) {
numbers.add(random.nextInt(100));
}
System.out.println("随机生成的数字为:" + numbers);
int maxPrime = 0;
for (int number : numbers) {
if (isPrime(number) && number > maxPrime) {
maxPrime = number;
}
}
if (maxPrime == 0) {
System.out.println("没有找到质数");
} else {
System.out.println("最大的质数为:" + maxPrime);
}
Collections.sort(numbers);
System.out.println("排序后的数字为:" + numbers);
}
private static boolean isPrime(int number) {
if (number <= 1) {
return false;
}
for (int i = 2; i <= Math.sqrt(number); i++) {
if (number % i == 0) {
return false;
}
}
return true;
}
}
```
这个程序会先让用户输入需要生成的数字个数,然后使用Random类的nextInt()方法生成随机数字,并存储到一个List中。接着,它会遍历这些数字,找到最大的质数。isPrime()方法用于判断一个数字是否为质数。最后,使用Collections.sort()方法对数字进行排序,并输出结果。
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