finder算法python代码
时间: 2023-07-23 21:09:29 浏览: 107
以下是一个简单的使用Finder算法的Python代码示例:
```python
import math
class Node:
def __init__(self, x, y):
self.x = x
self.y = y
class Finder:
def __init__(self, start, end, obstacles):
self.start = start
self.end = end
self.obstacles = obstacles
def find_path(self):
path = []
open_list = [self.start]
closed_list = []
while len(open_list) > 0:
current_node = open_list[0]
for node in open_list:
if self.distance(node, self.end) < self.distance(current_node, self.end):
current_node = node
open_list.remove(current_node)
closed_list.append(current_node)
if current_node == self.end:
while current_node != self.start:
path.append(current_node)
current_node = current_node.parent
path.append(self.start)
break
neighbors = self.get_neighbors(current_node)
for neighbor in neighbors:
if neighbor in closed_list or neighbor in open_list:
continue
neighbor.parent = current_node
neighbor.g = current_node.g + self.distance(current_node, neighbor)
neighbor.h = self.distance(neighbor, self.end)
neighbor.f = neighbor.g + neighbor.h
open_list.append(neighbor)
path.reverse()
return path
def get_neighbors(self, node):
neighbors = []
for i in range(-1, 2):
for j in range(-1, 2):
if i == 0 and j == 0:
continue
x = node.x + i
y = node.y + j
if x < 0 or y < 0 or x >= len(self.obstacles) or y >= len(self.obstacles[0]):
continue
if self.obstacles[x][y] == 1:
continue
neighbors.append(Node(x, y))
return neighbors
def distance(self, node1, node2):
return math.sqrt((node1.x - node2.x)**2 + (node1.y - node2.y)**2)
```
这个代码实现了一个Finder类,用于在给定起点、终点和障碍物的情况下搜索路径。在调用`find_path`方法时,它将返回一个包含路径节点的列表,每个节点都包含`x`和`y`坐标属性。
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