帮我写一个解压并读取zip文件的java代码

好的，下面是对应的Java代码：

import java.io.*;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;

public class UnzipAndReadZipFile {
    public static void main(String[] args) {
        String zipFilePath = "path/to/zip/file.zip";
        String outputFolder = "path/to/unzip/folder";

        unzipAndRead(zipFilePath, outputFolder);
    }

    public static void unzipAndRead(String zipFilePath, String outputFolder) {
        try {
            File folder = new File(outputFolder);
            if (!folder.exists()) {
                folder.mkdir();
            }

            ZipInputStream zipInputStream = new ZipInputStream(new FileInputStream(zipFilePath));
            ZipEntry zipEntry = zipInputStream.getNextEntry();

            while (zipEntry != null) {
                String fileName = zipEntry.getName();
                File newFile = new File(outputFolder + File.separator + fileName);

                if (zipEntry.isDirectory()) {
                    newFile.mkdirs();
                } else {
                    FileOutputStream fos = new FileOutputStream(newFile);
                    byte[] buffer = new byte[1024];
                    int len;
                    while ((len = zipInputStream.read(buffer)) > 0) {
                        fos.write(buffer, 0, len);
                    }
                    fos.close();
                }

                zipEntry = zipInputStream.getNextEntry();
            }

            zipInputStream.closeEntry();
            zipInputStream.close();

            System.out.println("Unzipped and read the zip file successfully.");
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

这个代码可以解压并读取指定的Zip文件，将其内容解压到指定的文件夹中。如果需要修改文件路径，可以将代码中的相应路径替换成实际的路径即可。