generate 40,000 (200x200) 2-dimension data points based on cross in tray functon

我可以回答您的第一个问题。为了基于 "cross in tray" 函数生成 40,000 个二维数据点，我们需要定义一个坐标系，以及一个函数来计算每个点的值。 "cross in tray" 函数的公式如下：

f(x,y) = -0.0001 * (abs(sin(x) * sin(y) * exp(abs(100 - sqrt(x^2 + y^2)/pi))) + 1)^0.1

我们可以在 [0,200] 的范围内生成 x 和 y 坐标。然后按照以下方式计算每个点的值：

z = f(x,y)

然后，您可以将这些坐标和相应的 z 值保存为一个 CSV 文件或任何其他支持二进制格式的文件。注意，由于 "cross in tray" 函数的上限和下限是相等的，因此该函数将生成一个具有 X 型轮廓的形状。

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give me matlab code about generate 40,000 (200x200) 2-dimension data points based on cross in tray functon

Sure, here's the Matlab code for generating 40,000 (200x200) two-dimensional data points based on the cross in tray function:

% Define range of x and y values
x = linspace(-10, 10, 200);
y = linspace(-10, 10, 200);

% Create a meshgrid of x and y values
[X,Y] = meshgrid(x,y);

% Evaluate the cross in tray function for each x-y pair
Z = -(abs(sin(X).*sin(Y).*exp(abs(100-sqrt(X.^2+Y.^2)/pi)))+1).^(-0.1);

% Flatten Z into a column vector for easier manipulation
Z = Z(:);

% Combine X,Y, and Z vectors into a 40,000 x 3 matrix
data_matrix = [X(:), Y(:), Z];

Hope that helps! Let me know if you have any other questions.