多机器人路径规划的代码_开源了！机器人技术常用的路径规划算法（含动画演示）...

这是一个非常有用的开源代码，特别是对于机器人技术中的路径规划算法。这个代码库提供了多种常用的路径规划算法，包括 A* 算法、Dijkstra 算法、RRT 算法等，并且提供了动画演示，便于理解和学习这些算法。

这个代码库的使用非常简单，只需要下载代码，配置环境后即可运行。其中的动画演示非常直观，可以帮助用户更好地理解算法的原理和过程。

此外，这个代码库还支持多机器人路径规划，这对于机器人协作系统的开发非常有用。多机器人路径规划可以帮助机器人避免冲突和碰撞，实现高效的协作任务。

总之，这个开源代码库是一个非常有价值的资源，对于机器人技术的研究和开发都非常有帮助。

相关问题

A星算法的多机器人路径规划的python代码

### 回答1：
A星算法是一种用于解决路径规划问题的算法，它可以用于单机器人和多机器人的情况。下面是一段使用 Python 实现多机器人路径规划的代码示例：

import heapq
import numpy as np

def a_star(grid, start, goal, robot_starts, robot_goals):
    def heuristic(position, goal):
        # 计算启发函数（曼哈顿距离）
        return np.abs(position[0] - goal[0]) + np.abs(position[1] - goal[1])

    def get_neighbors(position, grid):
        # 获取当前位置的邻居
        row, col = position
        neighbors = []
        if row > 0 and grid[row-1, col] != 1:
            neighbors.append((row-1, col))
        if row < grid.shape[0]-1 and grid[row+1, col] != 1:
            neighbors.append((row+1, col))
        if col > 0 and grid[row, col-1] != 1:
            neighbors.append((row, col-1))
        if col < grid.shape[1]-1 and grid[row, col+1] != 1:
            neighbors.append((row, col+1))
        return neighbors

    def reconstruct_path(came_from, current):
        # 通过 came_from 数组重建路径
        path = [current]
        while current in came_from:
            current = came_from[current]
            path.append(current)
        path.reverse()
        return path

    robot_num = len(robot_starts)
    closed_set = [set() for i in range(robot_num)]
    came_from = [{} for i in range(robot_num)]
    g_score = [{robot_starts[i]: 0} for i in range(robot_num)]
    f_score = [{robot_starts[i]: heuristic(robot_starts[i], goal)} for i in range(robot_num)]
    heap = [(f_score[i][robot_starts[i]], i, robot_starts[i]) for i in range(robot_num)]
    heapq.heapify(heap)

    while heap:
        f, robot_idx, current = heapq.heappop(heap)
        if current == goal:
            return [reconstruct_path(came_from[i], current) for i in range(robot_num)]

        closed_set[robot_idx].add(current)
         

### 回答2：
A星算法（A*）是一种常用于路径规划的算法，适用于多机器人路径规划问题。下面是一个使用Python实现A*算法来解决多机器人路径规划的示例代码。

import heapq

# 定义节点类
class Node:
def __init__(self, pos, g, h):
self.pos = pos # 当前节点的位置
self.g = g # 从起点到当前节点的实际距离
self.h = h # 从当前节点到终点的估算距离
self.f = self.g + self.h # f = g + h

# 定义节点比较函数，用于优先队列的排序
def __lt__(self, other):
return self.f < other.f

# 定义A*算法函数
def astar(start, goal, obstacles):
open_list = [] # 用优先队列存放待探索节点
closed_list = set() # 存放已探索节点的位置
heapq.heappush(open_list, start) # 将起点加入优先队列

while open_list:
current_node = heapq.heappop(open_list) # 取出f值最小的节点
if current_node.pos == goal.pos: # 到达目标节点，路径规划完成
return True

closed_list.add(current_node.pos) # 将当前节点置为已探索

# 遍历当前节点的相邻节点
for neighbor in get_neighbors(current_node, obstacles):
if neighbor.pos in closed_list: # 忽略已探索节点
continue

new_g = current_node.g + get_distance(current_node, neighbor) # 新的g值
if neighbor in open_list:
if new_g < neighbor.g: # 当前路径更短，更新g值
neighbor.g = new_g
else:
neighbor.g = new_g
heapq.heappush(open_list, neighbor) # 加入优先队列

return False # 未找到路径

# 获取相邻节点
def get_neighbors(node, obstacles):
neighbors = []
dx = [-1, 0, 1, 0] # 定义上下左右四个方向
dy = [0, 1, 0, -1]

for i in range(4):
x = node.pos[0] + dx[i]
y = node.pos[1] + dy[i]

# 判断相邻节点是否合法
if x < 0 or x >= len(obstacles) or y < 0 or y >= len(obstacles[0]) or obstacles[x][y] == 1:
continue

h = get_distance(Node((x, y), 0, 0), goal) # 估算到目标节点的距离
neighbors.append(Node((x, y), node.g + 1, h))

return neighbors

# 获取节点间的距离（此处采用曼哈顿距离）
def get_distance(node1, node2):
return abs(node1.pos[0] - node2.pos[0]) + abs(node1.pos[1] - node2.pos[1])

# 示例使用
start = Node((0, 0), 0, 0) # 起点
goal = Node((5, 5), 0, 0) # 终点
obstacles = [[0, 1, 0, 0, 0, 0],
[0, 1, 0, 1, 1, 0],
[0, 0, 0, 0, 0, 0],
[0, 0, 0, 1, 1, 0],
[0, 1, 0, 0, 0, 0],
[0, 0, 0, 0, 1, 0]]

success = astar(start, goal, obstacles) # 运行A*算法

if success:
print("找到路径")
else:
print("未找到路径")

以上代码是一个简单的示例，实现了多机器人路径规划的A*算法。其中，`start`和`goal`分别表示起点和终点，`obstacles`表示障碍物的矩阵。在运行代码后，将输出成功找到路径或未找到路径的提示。  

### 回答3：
A星算法是一种常用的路径规划算法，多机器人路径规划是指多个机器人同时进行路径规划。下面是一个基于Python的多机器人路径规划的A星算法代码：

import heapq

class PriorityQueue:
def __init__(self):
self.elements = []

def empty(self):
return len(self.elements) == 0

def put(self, item, priority):
heapq.heappush(self.elements, (priority, item))

def get(self):
return heapq.heappop(self.elements)[1]

class Node:
def __init__(self, position, g=0, h=0):
self.position = position
self.g = g
self.h = h
self.f = g + h

def heuristic(a, b):
return abs(b[0] - a[0]) + abs(b[1] - a[1])

def a_star(graph, start, goal):
open_set = PriorityQueue()
open_set.put(start, 0)
came_from = {}
g_score = {start: 0}
f_score = {start: heuristic(start, goal)}

while not open_set.empty():
current = open_set.get()

if current == goal:
path = []
while current in came_from:
path.append(current)
current = came_from[current]
path.append(start)
path.reverse()
return path

for neighbor in graph[current]:
temp_g_score = g_score[current] + 1
if neighbor not in g_score or temp_g_score < g_score[neighbor]:
came_from[neighbor] = current
g_score[neighbor] = temp_g_score
f_score[neighbor] = temp_g_score + heuristic(neighbor, goal)
if neighbor not in open_set.elements:
open_set.put(neighbor, f_score[neighbor])

return None

graph = {
(0, 0): [(0, 1)],
(0, 1): [(0, 0), (1, 1)],
(1, 0): [(1, 1)],
(1, 1): [(0, 1), (1, 0)]
}

start = (0, 0)
goal = (1, 1)
path = a_star(graph, start, goal)
if path:
print("Path found:", path)
else:
print("Path not found.")

以上是一个简单的多机器人路径规划的A星算法的Python代码。代码中使用了优先队列实现open_set，并通过一个字典来记录每个节点的g_score和f_score。heuristic函数用来计算启发式值，指示节点到目标节点的估计距离。a_star函数中使用了A星算法来进行路径规划。最后，通过调用a_star函数来执行路径规划，并输出路径结果。

机器人路径规划Dijkstra算法代码

以下是使用Dijkstra算法实现机器人路径规划的代码示例：

import heapq

def dijkstra(graph, start, end):
    # 初始化距离字典和前驱节点字典
    distances = {node: float('inf') for node in graph}
    distances[start] = 0
    predecessors = {node: None for node in graph}

    # 创建优先队列并将起始节点加入队列
    queue = [(0, start)]

    while queue:
        # 弹出队列中距离最小的节点
        current_distance, current_node = heapq.heappop(queue)

        # 如果当前节点已经被访问过，则跳过
        if current_distance > distances[current_node]:
            continue

        # 遍历当前节点的邻居节点
        for neighbor, weight in graph[current_node].items():
            distance = current_distance + weight

            # 如果找到了更短的路径，则更新距离和前驱节点
            if distance < distances[neighbor]:
                distances[neighbor] = distance
                predecessors[neighbor] = current_node

                # 将邻居节点加入优先队列
                heapq.heappush(queue, (distance, neighbor))

    # 构建最短路径
    path = []
    current_node = end
    while current_node is not None:
        path.insert(0, current_node)
        current_node = predecessors[current_node]

    return path

# 示例图形表示
graph = {
    'A': {'B': 5, 'C': 1},
    'B': {'A': 5, 'C': 2, 'D': 1},
    'C': {'A': 1, 'B': 2, 'D': 4, 'E': 8},
    'D': {'B': 1, 'C': 4, 'E': 3, 'F': 6},
    'E': {'C': 8, 'D': 3},
    'F': {'D': 6}
}

start_node = 'A'
end_node = 'F'

# 调用Dijkstra算法求解最短路径
shortest_path = dijkstra(graph, start_node, end_node)
print("最短路径:", shortest_path)