现有一个List<BarCodeRedisDTO> dtos ，BarCodeRedisDTO中有goodsCode、goodsPrice。现在需要统计出每一个goodsCode有几个。返回一个OrderUserCashBackGoodsInfoDto，OrderUserCashBackGoodsInfoDto中有goodsCode、goodsPrice、count。count就表示同一个goodsCode的数量

好的，根据你的要求，我可以给出以下代码实现：

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

public class Main {
    public static void main(String[] args) {
        // 假设这是你的List<BarCodeRedisDTO> dtos
        List<BarCodeRedisDTO> dtos = new ArrayList<>();
        dtos.add(new BarCodeRedisDTO("code1", 10));
        dtos.add(new BarCodeRedisDTO("code2", 20));
        dtos.add(new BarCodeRedisDTO("code1", 10));
        dtos.add(new BarCodeRedisDTO("code3", 30));
        dtos.add(new BarCodeRedisDTO("code1", 10));

        // 统计每一个goodsCode的数量
        Map<String, Integer> countMap = new HashMap<>();
        for (BarCodeRedisDTO dto : dtos) {
            String goodsCode = dto.getGoodsCode();
            int count = countMap.getOrDefault(goodsCode, 0);
            countMap.put(goodsCode, count + 1);
        }

        // 构造返回结果
        List<OrderUserCashBackGoodsInfoDto> result = new ArrayList<>();
        for (BarCodeRedisDTO dto : dtos) {
            String goodsCode = dto.getGoodsCode();
            int goodsPrice = dto.getGoodsPrice();
            int count = countMap.get(goodsCode);
            OrderUserCashBackGoodsInfoDto infoDto = new OrderUserCashBackGoodsInfoDto(goodsCode, goodsPrice, count);
            // 防止重复添加
            if (!result.contains(infoDto)) {
                result.add(infoDto);
            }
        }

        // 打印结果
        for (OrderUserCashBackGoodsInfoDto infoDto : result) {
            System.out.println(infoDto);
        }
    }
}

class BarCodeRedisDTO {
    private String goodsCode;
    private int goodsPrice;

    public BarCodeRedisDTO(String goodsCode, int goodsPrice) {
        this.goodsCode = goodsCode;
        this.goodsPrice = goodsPrice;
    }

    public String getGoodsCode() {
        return goodsCode;
    }

    public int getGoodsPrice() {
        return goodsPrice;
    }
}

class OrderUserCashBackGoodsInfoDto {
    private String goodsCode;
    private int goodsPrice;
    private int count;

    public OrderUserCashBackGoodsInfoDto(String goodsCode, int goodsPrice, int count) {
        this.goodsCode = goodsCode;
        this.goodsPrice = goodsPrice;
        this.count = count;
    }

    public String getGoodsCode() {
        return goodsCode;
    }

    public int getGoodsPrice() {
        return goodsPrice;
    }

    public int getCount() {
        return count;
    }

    @Override
    public boolean equals(Object obj) {
        if (this == obj) {
            return true;
        }
        if (obj == null || getClass() != obj.getClass()) {
            return false;
        }
        OrderUserCashBackGoodsInfoDto that = (OrderUserCashBackGoodsInfoDto) obj;
        return goodsCode.equals(that.goodsCode);
    }

    @Override
    public int hashCode() {
        return goodsCode.hashCode();
    }

    @Override
    public String toString() {
        return "OrderUserCashBackGoodsInfoDto{" +
                "goodsCode='" + goodsCode + '\'' +
                ", goodsPrice=" + goodsPrice +
                ", count=" + count +
                '}';
    }
}

代码中使用了Map来统计每一个goodsCode的数量，然后遍历原List构造返回结果，并防止重复添加。最后打印结果。由于这里只是一个示例，你需要根据实际情况进行修改。