c++求1+1/2+1/3+...+1/n

C++求1+1/2+1/3+...+1/n的代码如下：

#include <iostream>
using namespace std;
int main()
{
    int n;
    double sum = 0;
    cout << "请输入n的值：";
    cin >> n;
    for (int i = 1; i <= n; i++)
        sum += 1.0 / i;
    cout << "结果为：" << sum << endl;
    return 0;
}