TypeError: classification() missing 1 required positional argument: 'self'
时间: 2023-10-24 21:04:50 浏览: 135
TypeError: missing 1 required keyword-only argument-python中的报错问题
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This error typically occurs when a method of a class is called without an instance of the class being created first. Here is an example of how this error can occur:
```
class MyClassifier:
def __init__(self):
self.model = None
def fit(self, X, y):
# code to train a machine learning model
def predict(self, X):
# code to make predictions using the trained model
def classification(X):
clf = MyClassifier()
clf.fit(X, y) # this line creates an instance of MyClassifier and calls the fit method
y_pred = clf.predict(X) # this line calls the predict method on the same instance of MyClassifier
return y_pred
```
If the `classification` function is called like this:
```
X = [1, 2, 3, 4, 5]
classification(X)
```
It will result in the following error:
```
TypeError: classification() missing 1 required positional argument: 'self'
```
This is because the `fit` and `predict` methods of `MyClassifier` require an instance of the class to be created first, and this is not happening in the `classification` function. To fix this error, an instance of `MyClassifier` needs to be created before calling the `fit` and `predict` methods, like this:
```
def classification(X):
clf = MyClassifier() # create an instance of MyClassifier
clf.fit(X, y) # call the fit method on the instance of MyClassifier
y_pred = clf.predict(X) # call the predict method on the same instance of MyClassifier
return y_pred
```
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