java request.getrequesturi乱码
时间: 2023-05-16 09:05:37 浏览: 100
如果您的请求URI中包含非ASCII字符,则可能会出现乱码问题。您可以使用URLEncoder.encode()方法对URI进行编码,以确保它包含的所有字符都是ASCII字符。例如,您可以使用以下代码获取编码后的请求URI:
String encodedURI = URLEncoder.encode(request.getRequestURI(), "UTF-8");
然后,您可以使用编码后的URI来执行您的操作。
相关问题
request.getrequesturi
request.getRequestURI是一个Java Servlet API中的方法,用于获取客户端请求的URI(Uniform Resource Identifier),即请求的URL路径。URI包括协议、主机名、端口号和路径等信息,可以用于确定客户端请求的资源。例如,如果客户端请求的URL为http://www.example.com/index.html,则request.getRequestURI将返回"/index.html"。
request.getRequestURI().contains
This is a method call in Java that checks whether the URI (Uniform Resource Identifier) contained in the HTTP request matches a particular string or pattern. The getRequestURI() method returns the URI of the request, which is the part of the URL after the domain name and port number. The contains() method is then used to check whether a particular string or pattern is present in the URI.
For example, if the request URI is "https://example.com/products/12345/details", you could use the following code to check if it contains the string "products":
```
if(request.getRequestURI().contains("products")){
//do something
}
```
In this case, the condition would be true, and the code inside the if block would be executed.