Java代码 根据输入的年份判断是否为闰年，如果为世纪闰年输出“Century l eap year.”，如果为普通闰年输出“leap year.”，如果不为闰年输出“It i s not leap year.”。并设计测试数据进行判定覆盖测试。

代码如下：

import java.util.Scanner;

public class LeapYear {

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Please enter a year: ");
int year = sc.nextInt();
sc.close();
boolean isLeapYear = false;

if (year % 4 == 0) {
if (year % 100 == 0) {
if (year % 400 == 0) {
isLeapYear = true;
}
} else {
isLeapYear = true;
}
}

if (isLeapYear) {
if (year % 100 == 0) {
System.out.println("Century leap year.");
} else {
System.out.println("Leap year.");
}
} else {
System.out.println("It is not leap year.");
}
}

}

测试数据如下：

1. 输入2000，期望输出：Century leap year.
2. 输入2020，期望输出：Leap year.
3. 输入1900，期望输出：It is not leap year.
4. 输入2021，期望输出：It is not leap year.
5. 输入1600，期望输出：Century leap year.