请用python实现快速排序多线程版本

在 Python 中实现多线程版快速排序可以使用 `Thread` 对象或 `multiprocessing` 模块中的 `Process` 对象。

以下是使用 `Thread` 对象的示例代码：

import threading

def quick_sort(arr):
    if len(arr) <= 1:
        return arr
    pivot = arr[len(arr) // 2]
    left = [x for x in arr if x < pivot]
    middle = [x for x in arr if x == pivot]
    right = [x for x in arr if x > pivot]
    left = quick_sort(left)
    right = quick_sort(right)
    return left + middle + right

def sort_thread(arr):
    return quick_sort(arr)

def multi_thread_quick_sort(arr):
    if len(arr) <= 1:
        return arr
    pivot = arr[len(arr) // 2]
    left = [x for x in arr if x < pivot]
    middle = [x for x in arr if x == pivot]
    right = [x for x in arr if x > pivot]
    t1 = threading.Thread(target=sort_thread, args=(left,))
    t2 = threading.Thread(target=sort_thread, args=(right,))
    t1.start()
    t2.start()
    t1.join()
    t2.join()
    return left + middle + right

以下是使用 `Process` 对象的示例代码：

import multiprocessing

def quick_sort(arr):
    if len(arr) <= 1:
        return arr
    pivot = arr[len(arr) // 2]
    left = [x for x in arr if x < pivot]
    middle = [x for x in arr if x == pivot]
    right = [x for x in arr if x > pivot]
    left = quick_sort(left)
    right = quick_sort(right)
    return left + middle + right

def sort_process(arr, q):
    q.put(quick_sort(arr))

def multi_process_quick_sort(arr):
    if len(arr) <= 1:
        return arr
    pivot = arr[len(arr) // 2]
    left = [x for x in arr if x < pivot]
    middle = [x for x in arr if x == pivot]
    right = [x for x in arr if x > pivot]
    q1 = multiprocessing.Queue()
    q2 = multiprocessing.Queue()
    p1 = multiprocessing.Process(target=sort_process, args=(left, q1))
    p2 = multiprocessing.Process(target=sort_process, args=(right, q2))
    p1.start()
    p2.start()
    p1.join()
    p2.join()