int k =7; do { System.out.println(k--); k--; } while(k>=0);
时间: 2023-06-19 14:10:36 浏览: 36
这段代码的输出结果是什么?
输出结果是:7 5 3 1。
代码中使用了 do-while 循环,先执行循环体中的语句,然后再判断循环条件。在第一次循环时,k 的值为 7,输出 7 后,k 自减 1,变为 6,再自减 1 变为 5,此时 k 大于等于 0,因此继续循环。接下来的输出依次是 5、3、1。当 k 的值减为 -1 时,不满足循环条件,循环结束。
相关问题
package sad; import java.util.*; public class shd { public static void main(String[] args) { Scanner scan=new Scanner(System.in); System.out.print("请输入一个正整数:"); int n=s.nextInt(); int k=2; System.out.print(n+"="); while(k<=n) { if(k==n) { System.out.println(n); break; }else if(n%k==0) {System.out.print(k+"*"); n=n/k; } else k++; } } }
在您提供的代码中,有一个错误。在第8行,您定义了一个Scanner对象,但在第10行却使用了一个未定义的变量s来调用nextInt()方法,应该改为使用定义过的Scanner对象scan:
```java
int n = scan.nextInt();
```
这样,程序就可以正确读取控制台输入的整数了。
int a=0; int c=0; do{ –-c; a=a-1; }while(a>0); System.out.println(a+" "+c);
As an AI language model, I can see that the given code will result in a syntax error because of the missing "+" or "-" operator between "a" and the string to print. Here's the corrected code with the assumption that the missing operator is "-":
```
int a = 0;
int c = 0;
do {
--c;
a = a - 1;
} while (a > 0);
System.out.println(a + " " + c);
```
This code will decrement the value of "c" by 1 in each iteration and "a" by 1 until "a" becomes less than or equal to 0. Finally, it will print the value of "a" and "c" separated by a space. Since the initial value of "a" is 0, the loop will not execute even once, resulting in the output "0 -1".