$curl = curl_init(); $url = "https://query2.finance.yahoo.com/v1/finance/screener?crumb=XpTM.zvF16Z&lang=en-US&region=US&formatted=true&corsDomain=finance.yahoo.com"; // 替换为实际请求URL $data = '{"offset":6325,"size":25,"sortField":"dayvolume","sortType":"desc","quoteType":"equity","query":{"operator":"eq","operands":["region","in"]},"userId":"","userIdType":"guid"}'; curl_setopt($curl, CURLOPT_URL, $url); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_POST, true); curl_setopt($curl, CURLOPT_POSTFIELDS, $data); curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false); curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json')); print_r(curl_exec($curl));//$dd=json_decode(curl_exec($curl),true); curl_close($curl); exit;里面的请求数据并不支持json，请帮我修改成正确的

您好！根据您提供的代码，您想通过POST请求向"https://query2.finance.yahoo.com/v1/finance/screener"发送数据，并获取响应结果。为了确保请求数据正确，您可以将请求数据编码为JSON格式，并在请求头中指定Content-Type为application/json。以下是修改后的代码示例：

$curl = curl_init();
$url = "https://query2.finance.yahoo.com/v1/finance/screener?crumb=XpTM.zvF16Z&lang=en-US&region=US&formatted=true&corsDomain=finance.yahoo.com"; // 替换为实际请求URL
$data = array(
    "offset" => 6325,
    "size" => 25,
    "sortField" => "dayvolume",
    "sortType" => "desc",
    "quoteType" => "equity",
    "query" => array(
        "operator" => "eq",
        "operands" => array("region", "in")
    ),
    "userId" => "",
    "userIdType" => "guid"
);
$jsonData = json_encode($data);

curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_POST, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, $jsonData);
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($curl, CURLOPT_HTTPHEADER, array('Content-Type: application/json'));

$response = curl_exec($curl);
print_r($response);

curl_close($curl);
exit;

这样，请求数据将被正确编码为JSON格式，并作为POST请求发送到指定URL。请注意，我已经注释了您提供的`$dd=json_decode(curl_exec($curl),true);`行，因为您在此行之前已经使用`print_r($response);`打印了响应结果。

希望能帮到您！如果还有其他问题，请随时提问。