android wgs84转gcj02
时间: 2023-07-24 21:22:52 浏览: 129
要将WGS84坐标转换为GCJ02坐标,可以使用以下代码实现:
```java
public static double[] wgs84ToGcj02(double lat, double lon) {
double pi = 3.1415926535897932384626;
double a = 6378245.0;
double ee = 0.00669342162296594323;
double[] loc = new double[2];
if (outOfChina(lat, lon)) {
loc[0] = lat;
loc[1] = lon;
return loc;
} else {
double dLat = transformLat(lon - 105.0, lat - 35.0);
double dLon = transformLon(lon - 105.0, lat - 35.0);
double radLat = lat / 180.0 * pi;
double magic = Math.sin(radLat);
magic = 1 - ee * magic * magic;
double sqrtMagic = Math.sqrt(magic);
dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);
loc[0] = lat + dLat;
loc[1] = lon + dLon;
return loc;
}
}
private static boolean outOfChina(double lat, double lon) {
if (lon < 72.004 || lon > 137.8347)
return true;
if (lat < 0.8293 || lat > 55.8271)
return true;
return false;
}
private static double transformLat(double x, double y) {
double pi = 3.1415926535897932384626;
double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.sqrt(Math.abs(x));
ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;
ret += (20.0 * Math.sin(y * pi) + 40.0 * Math.sin(y / 3.0 * pi)) * 2.0 / 3.0;
ret += (160.0 * Math.sin(y / 12.0 * pi) + 320 * Math.sin(y * pi / 30.0)) * 2.0 / 3.0;
return ret;
}
private static double transformLon(double x, double y) {
double pi = 3.1415926535897932384626;
double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.sqrt(Math.abs(x));
ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;
ret += (20.0 * Math.sin(x * pi) + 40.0 * Math.sin(x / 3.0 * pi)) * 2.0 / 3.0;
ret += (150.0 * Math.sin(x / 12.0 * pi) + 300.0 * Math.sin(x / 30.0 * pi)) * 2.0 / 3.0;
return ret;
}
```
其中,传入的参数`lat`和`lon`分别表示待转换坐标的纬度和经度。返回的`loc`数组中,`loc[0]`表示转换后的纬度,`loc[1]`表示转换后的经度。
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