C++两个日期之间，分出日期的单数和双数

以下是一个简单的C++程序，可以计算两个日期之间的天数，并将其分为单数和双数。

#include <iostream>
using namespace std;

int isLeap(int year) {
   return ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0);
}

int getDays(int d, int m, int y) {
   int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
   if (isLeap(y)) days[1] = 29;
   int total = 0;
   for (int i = 0; i < m - 1; i++) {
      total += days[i];
   }
   total += d;
   return total;
}

int main() {
   int d1, m1, y1, d2, m2, y2;

   cout << "Enter first date (DD MM YYYY): ";
   cin >> d1 >> m1 >> y1;
   cout << "Enter second date (DD MM YYYY): ";
   cin >> d2 >> m2 >> y2;

   int days1 = getDays(d1, m1, y1);
   int days2 = getDays(d2, m2, y2);
   int diff = days2 - days1;

   cout << "Days between dates: " << diff << endl;
   if(diff%2==0){
      cout<<"The number of days between the two dates is even."<<endl;
   }
   else{
      cout<<"The number of days between the two dates is odd."<<endl;
   }
   return 0;
}

在程序中，`isLeap`函数用于检查给定年份是否为闰年。`getDays`函数计算给定日期的天数。最后，在主函数中，计算两个日期之间的天数，并检查它是否为偶数或奇数。