python函数实现1到100的偶数和
时间: 2023-06-03 11:01:47 浏览: 1750
可以使用以下代码实现1到100的偶数和:
```python
def even_sum(start, end):
"""Calculate the sum of even numbers between start and end."""
total = 0
for i in range(start, end+1):
if i % 2 == 0:
total += i
return total
sum = even_sum(1, 100)
print("The sum of even numbers between 1 and 100 is", sum)
```
输出结果为:
```
The sum of even numbers between 1 and 100 is 2550
```
相关问题
python函数求1到100的偶数和
可以使用以下函数来求1到100的偶数和:
```python
def sum_even_numbers():
sum = 0
for i in range(2, 101, 2):
sum += i
return sum
```
其中,使用 for 循环遍历范围为 2 到 100,步长为 2,即只取偶数,然后将偶数累加到 sum 中,最后返回 sum 即可。
python编写函数输出1-100偶数之和
编写函数输出1-100偶数之和。
解答:
可以使用循环来遍历1-100之间的数字,通过判断其是否为偶数来累加求和。具体实现如下:
```python
def sum_even_numbers():
sum = 0 # 初始化偶数之和
for num in range(1, 101): # 遍历1-100的数字
if num % 2 == 0: # 判断是否为偶数
sum += num # 累加求和
print('1-100偶数之和为:', sum)
```
调用该函数即可输出结果。
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