用python做一个色盲派对小游戏
时间: 2024-02-02 18:03:27 浏览: 27
好的,下面是一个简单的色盲派对小游戏的代码示例:
```python
import random
import tkinter as tk
# 颜色盲模拟器,用于生成色盲用户看到的颜色
def simulate_color_blindness(color, blindness_type):
if blindness_type == "protanopia":
return (color[1]*0.567 + color[2]*0.433, color[1]*0.558 + color[2]*0.442, 0)
elif blindness_type == "deuteranopia":
return (color[0]*0.625 + color[2]*0.375, color[0]*0.7 + color[2]*0.3, 0)
elif blindness_type == "tritanopia":
return (color[0]*0.95 + color[1]*0.05, color[0]*0.433 + color[1]*0.567, 0)
else:
return color
# 随机生成一组颜色
def generate_random_color():
return (random.randint(0, 255), random.randint(0, 255), random.randint(0, 255))
# 随机生成一组色盲用户看到的颜色
def generate_simulated_color(color, blindness_type):
return tuple(int(c) for c in simulate_color_blindness(color, blindness_type))
# 检查用户选择的颜色是否正确
def check_answer(color, user_choice):
return color == user_choice
# 游戏主函数
def play_game():
colors = ["protanopia", "deuteranopia", "tritanopia"]
color = generate_random_color()
color_choices = [generate_simulated_color(color, blindness_type) for blindness_type in colors]
root = tk.Tk()
# 显示颜色
color_label = tk.Label(root, bg="#%02x%02x%02x" % color, width=30, height=10)
color_label.pack()
# 显示选项
for i, choice in enumerate(color_choices):
choice_button = tk.Button(root, bg="#%02x%02x%02x" % choice, text="Option %d" % (i+1), width=30, height=5)
choice_button.pack()
# 绑定点击事件,检查答案
choice_button.bind("<Button-1>", lambda event, choice=choice: check_answer(color, choice))
root.mainloop()
play_game()
```
这个小游戏会在窗口中随机生成一组颜色,然后生成三个色盲用户看到的颜色作为选项。玩家需要选择他们认为是原始颜色的选项。如果选择正确,游戏会在窗口中显示“Correct!”,否则会显示“Incorrect!”。