Parallel computation

时间: 2023-08-16 18:03:53 浏览: 39
并行计算(Parallel computation)是指将一个大规模的计算任务,拆分成多个子任务,同时在多个处理器或计算节点上进行计算,以提高计算效率和速度的一种计算方式。 并行计算通常包括以下几个方面: 1. 任务拆分:将一个大规模计算任务拆分成多个子任务,每个子任务可以独立计算,同时保证整个计算任务的正确性和准确性。 2. 通信:在多个处理器或计算节点之间进行通信和数据交换,以保证整个计算任务的协同和同步。 3. 负载平衡:通过动态调整任务分配和计算资源,保证每个处理器或计算节点的计算负载相对均衡,避免出现瓶颈和资源浪费。 4. 任务调度:通过任务调度算法,将不同的计算任务分配给不同的处理器或计算节点,以最大化计算资源的利用效率和计算速度。 并行计算在科学计算、大数据分析、机器学习等众多领域中都有广泛应用,可以大大提高计算效率和速度,缩短计算时间,为科学研究和工程实践提供了重要支持和帮助。

c# 线程parallel

C#中的Parallel类提供了一种简单的方法来并行执行任务。它可以自动将任务分配给多个线程,并在完成后将结果合并。Parallel类可以用于处理大型数据集或执行需要较长时间的操作。 以下是Parallel类的基本使用方法: ```csharp using System; using System.Threading.Tasks; class Program { static void Main(string[] args) { Parallel.For(0, 10, i => { Console.WriteLine("Task {0} started", i); // Perform some computation Console.WriteLine("Task {0} completed", i); }); Console.WriteLine("All tasks completed"); Console.ReadLine(); } } ``` 在上面的示例中,Parallel.For方法将任务分配给多个线程。它接受三个参数:起始索引、结束索引和一个委托,该委托指定要执行的操作。在这种情况下,我们只是打印一些文本,但您可以将其替换为任何操作。 请注意,Parallel类使用的线程池,因此不需要手动创建线程。此外,它还提供了其他有用的方法,例如Parallel.ForEach和Parallel.Invoke,可用于执行不同类型的任务。

parallel matrix multiplication

Parallel matrix multiplication is a technique used in computer science to speed up matrix multiplication by breaking down the process into smaller computations that can be done simultaneously on multiple processors. This helps to reduce computation time and improve performance. Would you like me to explain it in more detail?


当然可以,以下是一个手写的Python函数np.histogram: python def histogram(a, bins=10, range=None): """ Compute the histogram of a set of data. Parameters ---------- a : array_like Input data. The histogram is computed over the flattened array. bins : int or sequence of scalars or str, optional If bins is an int, it defines the number of equal-width bins in the given range (10, by default). If bins is a sequence, it defines a monotonically increasing array of bin edges, including the rightmost edge, allowing for non-uniform bin widths. .. versionadded:: 1.11.0 If bins is a string from the list below, histogram will use the method chosen to calculate the optimal bin width and consequently the number of bins (see Notes for more detail on the estimators) from the data that falls within the requested range. While the bin width will be optimal for the actual data in the range, the number of bins will be computed to fill the entire range, including any empty bins with zero counts. Here are the possible values for the bins string: 'auto' Maximum of the 'sturges' and 'fd' estimators. Provides good all-around performance. 'fd' (Freedman Diaconis Estimator) Robust (resilient to outliers) estimator that takes into account data variability and data size. 'doane' An improved version of Sturges' estimator that works better with non-normal datasets. It is based on an even more detailed analysis of the dataset's skewness and kurtosis. 'scott' Less robust estimator that that takes into account data variability and data size. 'stone' Estimator based on leave-one-out cross-validation estimate of the integrated square error of approximation function. Can be regarded as a generalization of Scott's rule. More estimators are available in the scipy.stats module. .. versionadded:: 1.13.0 range : tuple or None, optional The lower and upper range of the bins. Lower and upper outliers are ignored. If not provided, range is (a.min(), a.max()). Range has no effect if bins is a sequence. If bins is a sequence or range is specified, autoscaling is based on the specified bin range instead of the range of x. Returns ------- hist : ndarray The values of the histogram. See density and weights for a description of the possible semantics. bin_edges : ndarray Return the bin edges (length(hist)+1). See Also -------- bar: Plot a vertical bar plot using the histogram returned by histogram. hist2d: Make a 2D histogram plot. histogramdd: Make a multidimensional histogram plot. scipy.stats.histogram: Compute histogram using scipy. Notes ----- All but the last (righthand-most) bin is half-open. In other words, if bins is [1, 2, 3, 4], then the first bin is [1, 2) (including 1, but excluding 2) and the second [2, 3). The last bin, however, is [4, 4], which includes 4. References ---------- .. [1] Examples -------- >>> np.histogram([1, 2, 1], bins=[0, 1, 2, 3]) (array([0, 2, 1]), array([0, 1, 2, 3])) >>> np.histogram(np.arange(4), bins=np.arange(5), density=True) (array([0.25, 0.25, 0.25, 0.25]), array([0, 1, 2, 3, 4])) >>> np.histogram([[1, 2, 1], [1, 0, 1]], bins=[0,1,2,3]) (array([1, 4, 1]), array([0, 1, 2, 3])) """ a = np.asarray(a) if not np.isfinite(a).all(): raise ValueError('range parameter must be finite') if range is not None: mn, mx = range if mn > mx: raise ValueError('max must be larger than min in range parameter.') if not (np.isfinite(mn) and np.isfinite(mx)): raise ValueError('range parameter must be finite.') keep = (a >= mn) & (a <= mx) if not keep.any(): return np.zeros(bins, dtype=np.intp), np.asarray([mn, mx]) a = a[keep] if bins is not None: bins = np.asarray(bins) if (np.diff(bins) < 0).any(): raise ValueError('bins must increase monotonically.') if len(bins) == 1: if np.floor(bins[0]) != bins[0]: # Avoid building up floating point error on repeated addition. widths = np.full(bins, (bins[0] - 0.5), dtype=np.float_) widths[0] = bins[0] - 0.5 else: widths = np.full(bins, bins[0]-0.5, dtype=np.float_) bins = np.arange(len(widths)+1, dtype=np.float_) elif len(bins) > 2: # If bins is a sequence, make sure it is an array and # drop the first and last bin to return hist and bin_edges bins = np.asarray(bins) if (np.diff(bins) < 0).any(): raise ValueError('bins must increase monotonically.') # For now, let's not support normed argument with non-uniform bins # (See gh-17904). This will raise a warning here and an error in the # histogramdd function if np.any(bins[1:-1] != np.around(bins[1:-1])): warnings.warn( "normed argument is ignored when non-uniform bins are used.") keep = (bins[:-1] != bins[1:]) if np.sum(keep) < len(bins)-1: # Some bins are non-empty. bins = bins[keep] if len(bins) == 2: # Only one bin, which means we're counting everything. return np.array([len(a)]), bins else: # This will ensure that we have len(bins)-1 bins. bins = np.concatenate( [bins[:1], bins[1:][keep], bins[-1:]]) widths = np.diff(bins) else: # All bins are empty. return np.zeros(len(bins)-1, int), bins else: # len(bins) == 2. widths = bins[1] - bins[0] else: bin_size = 1.0 if a.size > 0: bin_size = 1.01 * (a.max() - a.min()) / a.size bins = np.arange(a.min(), a.max() + bin_size, bin_size) widths = np.diff(bins) # We iterate over blocks here for two reasons: the first is that for # datasets with large numbers of bins, it is much faster to loop over the # blocks than to use fancy indexing to add contributions to the bins. # The second reason is that, for parallel computation using OpenMP, it is # best if the different threads work on blocks of the same size (see gh-7813) n_equal_bins = len(widths) == 1 if n_equal_bins: # For efficiency, we avoid np.digitize and compute the bin indices # directly as an integer array. The minimum value of a is mapped # to bin 0, the maximum to len(widths)-1. bin_edges = np.asarray([a.min() - 0.5*widths[0], a.max() + 0.5*widths[0]]) if bin_edges[0] == bin_edges[1]: # handle empty input array such as np.histogram([], bins=1) bin_edges[0] -= 0.5 bin_edges[1] += 0.5 if np.isinf(bin_edges).any(): raise ValueError( "autodetected range of [{}, {}] is not finite".format(*bin_edges)) bin_idxs = np.floor((a - bin_edges[0]) / widths[0]).astype(np.intp) else: bin_edges = bins bin_idxs = np.digitize(a, bins, right=False) - 1 # Ensure that the uppermost bin is non-empty if len(a) > 0 and bin_idxs[-1] == len(widths): bin_idxs[-1] -= 1 # Using bincount is faster than using np.histogram and then adding # the results together. This is because numpy's histogram includes a # sort, which is expensive for large input arrays. if weights is None: hist = np.bincount(bin_idxs, minlength=len(widths)) else: weights = np.asarray(weights) if weights.shape != a.shape: raise ValueError( 'weights should have the same shape as a.') if not np.isfinite(weights).all(): raise ValueError('weights must be finite') hist = np.bincount(bin_idxs, weights=weights, minlength=len(widths)) if density: # If the histogram is empty, then return an array of zeros. if hist.sum() == 0: return hist.astype(float), bin_edges else: hist = hist / hist.sum() if cumulative: hist = np.cumsum(hist) return hist, bin_edges 这个函数的功能与NumPy中的np.histogram函数基本相同。
As an AI language model, I do not have access to the concurrent module or any other modules of Python. However, I can provide a brief explanation of what the concurrent module is and what it is used for. The concurrent module is a built-in Python module that provides a high-level interface for asynchronously executing functions using threads or processes. It includes the futures module, which provides a way to execute a function asynchronously and retrieve its result later. The concurrent.futures module is typically used to speed up IO-bound tasks, such as network requests, by allowing multiple requests to be executed in parallel. The concurrent.futures module provides two classes for submitting tasks: ThreadPoolExecutor and ProcessPoolExecutor. Both classes provide a submit() method that takes a function and its arguments as input and returns a Future object. A Future object represents the result of an asynchronous computation that has not yet completed. The Future object can be used to check if the computation is complete and retrieve the result when it is. The concurrent.futures module also provides a wait() function that can be used to wait for multiple Future objects to complete. The wait() function takes a list of Future objects and blocks until all of them have completed. Overall, the concurrent.futures module provides a simple and convenient way to execute functions asynchronously and retrieve their results. It can be a useful tool for speeding up IO-bound tasks and improving the performance of Python applications.
循环神经网络的发展历程可以分为以下几个阶段: 1. 前馈神经网络:早期的神经网络是前馈网络,没有记忆功能,只能处理静态输入。这一阶段的代表模型是感知机和多层感知机。 2. Elman网络:1988年,Elman提出了一种简单的循环神经网络模型,称为Elman网络。这一模型利用前一时刻的状态作为当前时刻的输入,解决了前馈神经网络无法处理序列数据的问题。 3. Jordan网络:1997年,Jordan提出了一种基于Elman网络的改进模型,称为Jordan网络。Jordan网络在Elman网络的基础上,将前一时刻的输出作为当前时刻的输入,增强了网络的记忆能力。 4. 长短时记忆网络(LSTM):1997年,Hochreiter和Schmidhuber提出了一种新型的循环神经网络模型,称为长短时记忆网络(LSTM)。LSTM通过引入三个门控单元(输入门、遗忘门和输出门),有效地解决了传统循环神经网络的梯度消失和梯度爆炸问题,使得网络具有更好的记忆能力。 5. 双向循环神经网络(BRNN):1995年,Schuster和Paliwal提出了一种新型的循环神经网络模型,称为双向循环神经网络(BRNN)。BRNN在输入序列的两个方向上都有循环结构,可以有效地处理序列数据中的长期依赖关系。 6. 门控循环单元(GRU):2014年,Cho等人提出了一种新型的循环神经网络模型,称为门控循环单元(GRU)。GRU在LSTM的基础上,通过减少门控单元的数量和简化门控机制,实现了更快的训练速度和更小的模型尺寸。 参考文献: 1. Rumelhart, D. E., Hinton, G. E., & Williams, R. J. (1986). Learning representations by back-propagating errors. Nature, 323(6088), 533-536. 2. Elman, J. L. (1990). Finding structure in time. Cognitive science, 14(2), 179-211. 3. Jordan, M. I. (1986). Serial order: A parallel distributed processing approach. Technical Report CMU-CS-86-126, Carnegie Mellon University. 4. Hochreiter, S., & Schmidhuber, J. (1997). Long short-term memory. Neural computation, 9(8), 1735-1780. 5. Schuster, M., & Paliwal, K. K. (1997). Bidirectional recurrent neural networks. IEEE Transactions on Signal Processing, 45(11), 2673-2681. 6. Cho, K., Van Merrienboer, B., Gulcehre, C., Bougares, F., Schwenk, H., & Bengio, Y. (2014). Learning phrase representations using RNN encoder-decoder for statistical machine translation. arXiv preprint arXiv:1406.1078.



Contents Overview 1 Lesson 1: Index Concepts 3 Lesson 2: Concepts – Statistics 29 Lesson 3: Concepts – Query Optimization 37 Lesson 4: Information Collection and Analysis 61 Lesson 5: Formulating ...

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CSDN佛怒唐莲上传的视频均有对应的完整代码,皆可运行,亲测可用,适合小白; 1、代码压缩包内容 主函数:main.m; 调用函数:其他m文件;无需运行 运行结果效果图; 2、代码运行版本 Matlab 2019b;若运行有误,根据提示修改;若不会,私信博主; 3、运行操作步骤 步骤一:将所有文件放到Matlab的当前文件夹中; 步骤二:双击打开main.m文件; 步骤三:点击运行,等程序运行完得到结果; 4、仿真咨询 如需其他服务,可私信博主或扫描博客文章底部QQ名片; 4.1 博客或资源的完整代码提供 4.2 期刊或参考文献复现 4.3 Matlab程序定制 4.4 科研合作








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