在8086环境下用汇编语言编写、输入一个32位二进制数相加程序

以下是在8086环境下用汇编语言编写、输入一个32位二进制数相加程序的代码：

.model small
.stack 100h

.data
msg db 'Enter a 32-bit binary number: $'
result db 'The sum is: $'
num1 db 32 dup('$')
num2 db 32 dup('$')
sum db 33 dup('$')

.code
main proc
    mov ax, @data
    mov ds, ax

    ; Input first 32-bit binary number
    mov ah, 9
    lea dx, msg
    int 21h
    mov ah, 0Ah
    lea dx, num1
    int 21h

    ; Input second 32-bit binary number
    mov ah, 9
    lea dx, msg
    int 21h
    mov ah, 0Ah
    lea dx, num2
    int 21h

    ; Convert binary numbers to decimal
    call binToDec
    mov bx, ax
    call binToDec
    add bx, ax

    ; Convert sum to binary
    mov cx, 32 ; Counter for loop
    mov di, offset sum ; Offset for sum array
    mov ax, bx ; Result in AX
    mov bx, 2 ; Binary base
    mov dx, 0 ; Clear DX
sumLoop:
    div bx ; Divide by 2
    add dl, '0' ; Convert remainder to ASCII
    mov [di], dl ; Store in sum array
    dec di ; Decrement offset
    dec cx ; Decrement counter
    cmp cx, 0 ; Check if done
    jne sumLoop

    ; Output sum in binary
    mov ah, 9
    lea dx, result
    int 21h
    mov ah, 9
    lea dx, sum
    int 21h

    mov ah, 4ch ; Return control to DOS
    int 21h
main endp

; Convert binary number in num1 to decimal
; Result in AX
binToDec proc
    xor ax, ax ; Clear AX
    mov cx, 32 ; Counter for loop
    mov si, offset num1 ; Offset for num1 array
binLoop:
    mov dl, [si] ; Get next character in num1
    sub dl, '0' ; Convert to decimal
    mov bx, 2 ; Binary base
    mul bx ; Multiply by base (2)
    add ax, dx ; Add remainder
    inc si ; Increment offset
    dec cx ; Decrement counter
    cmp cx, 0 ; Check if done
    jne binLoop
    ret
binToDec endp

end main

这个程序会要求用户输入两个32位二进制数，然后将它们相加，最后输出结果。程序首先将输入的二进制数转换为十进制，然后将它们相加得到结果。最后，程序将结果转换为二进制并输出。