写一个c语言程序要求输入n,输出由*构成的菱形和纺锤形
时间: 2024-05-08 16:15:09 浏览: 17
这里提供两种方法,一种是使用循环语句,另一种是使用递归函数。
方法一:使用循环语句
```c
#include <stdio.h>
int main()
{
int n, i, j;
printf("请输入菱形和纺锤形的大小:");
scanf("%d", &n);
// 输出菱形
for (i = 1; i <= n; i++) {
for (j = 1; j <= n-i; j++) {
printf(" ");
}
for (j = 1; j <= 2*i-1; j++) {
printf("*");
}
printf("\n");
}
for (i = n-1; i >= 1; i--) {
for (j = 1; j <= n-i; j++) {
printf(" ");
}
for (j = 1; j <= 2*i-1; j++) {
printf("*");
}
printf("\n");
}
// 输出纺锤形
printf("\n");
for (i = 1; i <= n; i++) {
for (j = 1; j <= n-i; j++) {
printf(" ");
}
for (j = 1; j <= 2*i-1; j++) {
printf("*");
}
printf("\n");
}
for (i = n-1; i >= 1; i--) {
for (j = 1; j <= n-i; j++) {
printf(" ");
}
for (j = 1; j <= 2*i-1; j++) {
printf("*");
}
printf("\n");
}
for (i = 1; i <= n; i++) {
for (j = 1; j <= i-1; j++) {
printf(" ");
}
for (j = 1; j <= 2*(n-i)+1; j++) {
printf("*");
}
printf("\n");
}
for (i = n-1; i >= 1; i--) {
for (j = 1; j <= i-1; j++) {
printf(" ");
}
for (j = 1; j <= 2*(n-i)+1; j++) {
printf("*");
}
printf("\n");
}
return 0;
}
```
方法二:使用递归函数
```c
#include <stdio.h>
void print_line(int n, int i, int j, char c)
{
if (j <= n-i) {
printf(" ");
print_line(n, i, j+1, c);
} else if (j <= n+i-1) {
printf("%c", c);
print_line(n, i, j+1, c);
} else {
printf("\n");
}
}
void print_diamond(int n, int i, char c)
{
if (i <= n) {
print_line(n, i, 1, c);
print_diamond(n, i+1, c);
} else if (i <= 2*n-1) {
print_line(n, 2*n-i, 1, c);
print_diamond(n, i+1, c);
}
}
void print_rhombus(int n, int i, char c)
{
if (i <= n) {
print_line(n, i, 1, c);
print_rhombus(n, i+1, c);
} else if (i <= 2*n-1) {
print_line(n, 2*n-i, 1, c);
print_rhombus(n, i+1, c);
} else if (i <= 3*n-2) {
print_line(n, i-2*n+2, 1, c);
print_rhombus(n, i+1, c);
} else if (i <= 4*n-3) {
print_line(n, 4*n-i-2, 1, c);
print_rhombus(n, i+1, c);
}
}
int main()
{
int n;
char c = '*';
printf("请输入菱形和纺锤形的大小:");
scanf("%d", &n);
// 输出菱形
print_diamond(n, 1, c);
// 输出纺锤形
printf("\n");
print_rhombus(n, 1, c);
return 0;
}
```
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