use C program Enter a string s, and then enter a character c, find the character c in the string s. If it cannot be found, output "Not found"; If found, all characters in the string s starting from c will be output. [Input] In the first line, give a non empty string that is no longer than 80 characters and ends with enter; Give a character in the second line. [Output] Output the results in a row according to the requirements of the topic.

Sure, here's a C program that accomplishes the task you described:

#include <stdio.h>
#include <string.h>

int main() {
    char s[81], c;
    int i, j, found = 0;

    // Input the string
    printf("Enter a string: ");
    fgets(s, 81, stdin);
    s[strcspn(s, "\n")] = '\0'; // remove the newline character

    // Input the character
    printf("Enter a character: ");
    scanf("%c", &c);

    // Search for the character in the string
    for (i = 0; i < strlen(s); i++) {
        if (s[i] == c) {
            found = 1;
            for (j = i; j < strlen(s); j++) {
                printf("%c", s[j]);
            }
            break;
        }
    }

    // Output the result
    if (!found) {
        printf("Not found");
    }
    printf("\n");

    return 0;
}

You can compile and run this code to test it out.