python可以爬取的图片素材网址
时间: 2023-09-30 09:08:02 浏览: 58
以下是一些可以爬取图片素材的网站:
1. Unsplash (https://unsplash.com/)
2. Pexels (https://www.pexels.com/)
3. Pixabay (https://pixabay.com/)
4. Getty Images (https://www.gettyimages.com/)
5. Shutterstock (https://www.shutterstock.com/)
6. Freepik (https://www.freepik.com/)
7. Flaticon (https://www.flaticon.com/)
8. VectorStock (https://www.vectorstock.com/)
9. 123RF (https://www.123rf.com/)
10. iStock (https://www.istockphoto.com/)
请注意,使用这些网站上的图片素材时,需要遵守其使用规定和版权政策,以避免侵权问题。
相关问题
python爬虫爬取图片
以下是Python爬虫爬取图片的基本步骤:
1. 导入必要的模块
```python
import requests
from bs4 import BeautifulSoup
import os
```
2. 获取网页源代码
```python
url = 'https://www.example.com' # 要爬取图片的网址
response = requests.get(url)
html = response.text
```
3. 解析HTML代码
```python
soup = BeautifulSoup(html, 'html.parser')
```
4. 查找图片链接
```python
img_tags = soup.find_all('img')
img_urls = [img['src'] for img in img_tags]
```
5. 下载图片
```python
for url in img_urls:
response = requests.get(url)
filename = os.path.basename(url) # 获取文件名
with open(filename, 'wb') as f:
f.write(response.content)
```
完整的Python爬虫爬取图片的代码如下:
```python
import requests
from bs4 import BeautifulSoup
import os
url = 'https://www.example.com'
response = requests.get(url)
html = response.text
soup = BeautifulSoup(html, 'html.parser')
img_tags = soup.find_all('img')
img_urls = [img['src'] for img in img_tags]
for url in img_urls:
response = requests.get(url)
filename = os.path.basename(url)
with open(filename, 'wb') as f:
f.write(response.content)
```
注意:爬取网站的图片需要遵守相关法律法规,不得侵犯他人权益和隐私。
如何用python爬虫爬取图片
当使用Python进行爬虫时,可以使用第三方库如Requests、BeautifulSoup和Scrapy来实现。以下是一种基本的方法来使用Python爬虫爬取图片:
1. 导入所需的库:
```python
import requests
from bs4 import BeautifulSoup
```
2. 发送HTTP请求获取网页内容:
```python
url = "待爬取的网页URL"
response = requests.get(url)
```
3. 解析网页内容:
```python
soup = BeautifulSoup(response.text, "html.parser")
```
4. 定位图片标签:
```python
image_tags = soup.find_all("img")
```
5. 遍历图片标签并下载图片:
```python
for img in image_tags:
img_url = img["src"]
img_data = requests.get(img_url).content
with open("保存路径/文件名.jpg", "wb") as f:
f.write(img_data)
```
请注意,上述代码仅为基本示例,实际应用中可能需要处理更多的异常情况和优化代码。