用python语言编写连连看小游戏

好的，下面是用 Python 语言编写的连连看小游戏的代码：

import random

# 游戏地图的大小
MAP_SIZE = 10

# 游戏地图
game_map = [[' ' for x in range(MAP_SIZE)] for y in range(MAP_SIZE)]

# 游戏方块
blocks = ['A', 'B', 'C', 'D', 'E']

# 随机在地图上生成方块
for block in blocks:
    for i in range(2):
        x = random.randint(0, MAP_SIZE - 1)
        y = random.randint(0, MAP_SIZE - 1)
        game_map[y][x] = block

# 打印游戏地图
def print_map():
    for row in game_map:
        print(' '.join(row))

# 判断两个方块是否可以消除
def can_remove(x1, y1, x2, y2):
    if game_map[y1][x1] != game_map[y2][x2]:
        return False
    if x1 == x2 and y1 == y2:
        return False
    if x1 == x2:
        for y in range(min(y1, y2) + 1, max(y1, y2)):
            if game_map[y][x1] != ' ':
                return False
        return True
    if y1 == y2:
        for x in range(min(x1, x2) + 1, max(x1, x2)):
            if game_map[y1][x] != ' ':
                return False
        return True
    return False

# 消除两个方块
def remove(x1, y1, x2, y2):
    game_map[y1][x1] = ' '
    game_map[y2][x2] = ' '

# 判断游戏是否结束
def is_game_over():
    for y in range(MAP_SIZE):
        for x in range(MAP_SIZE):
            if game_map[y][x] != ' ':
                for y2 in range(y, MAP_SIZE):
                    x2_start = x + 1 if y2 == y else 0
                    for x2 in range(x2_start, MAP_SIZE):
                        if can_remove(x, y, x2, y2):
                            return False
    return True

# 游戏循环
while True:
    print_map()
    if is_game_over():
        print('Game Over!')
        break
    x1, y1, x2, y2 = map(int, input('Please enter two positions to remove: ').split())
    if can_remove(x1, y1, x2, y2):
        remove(x1, y1, x2, y2)
    else:
        print('Invalid positions!')

这个连连看小游戏使用二维数组来表示游戏地图，使用随机数来在地图上生成方块。玩家需要在输入两个方块的位置后，程序判断这两个方块是否可以消除，如果可以，则将它们从地图上删除。当地图上没有可以消除的方块时，游戏结束。