已知Point(点)类，点类的公有派生类Circle(圆)类，圆类的公有派生Cylinder(圆柱体)类如下： class Point { public: virtual double area() { return 0; } }; class Circle:public Point { protected: double m_radius; public: Circle(double r); virtual double area(); }; class Cylinder:public Circle { private: double m_high; public: Cylinder(double r, double h); virtual double area(); }; 试完成成员函数的定义，在主函数中输入圆的半径和圆柱的高，利用指向基类的指针，分别输出圆的面积和圆柱体的表面积。 Input 2个数，分别代表圆的半径和圆柱的高。 Output 圆的面积和圆柱体的表面积(取2位小数)。 Sample Input 1 1.5 2 Sample Output 1 7.06 32.97用c++写出此代码

#include <iostream>
#include <iomanip>
using namespace std;

class Point {
public:
    virtual double area() { return 0; }
};

class Circle : public Point {
protected:
    double m_radius;
public:
    Circle(double r) : m_radius(r) {}
    virtual double area() { return 3.14 * m_radius * m_radius; }
};

class Cylinder : public Circle {
private:
    double m_high;
public:
    Cylinder(double r, double h) : Circle(r), m_high(h) {}
    virtual double area() { return 2 * Circle::area() + 2 * 3.14 * m_radius * m_high; }
};

int main() {
    double r, h;
    cin >> r >> h;
    Point* p1 = new Circle(r);
    Point* p2 = new Cylinder(r, h);
    cout << fixed << setprecision(2) << p1->area() << " " << p2->area() << endl;
    delete p1;
    delete p2;
    return 0;
}