请帮我优化这段代码 // 下单 if (this.pWorkOrder.orderState === '20') { this.pWorkOrder.checkRequirements = this.description; } // 接单 if (this.pWorkOrder.orderState === '30') { this.pWorkOrder.checkRequirements = this.description; } // 反馈 if (this.pWorkOrder.orderState === '40') { if (this.pictureDet.length <= 0) { this.$tip.error(`${this.popupSitch.image.label}必填`); return; } this.pWorkOrder.checkRequirements = this.description; this.pWorkOrder.mPicture = this.pictureDet.join(','); } // 审核关闭 if (this.pWorkOrder.orderState === '50') { this.pWorkOrder.checkRequirements = this.description; }

可以将重复的代码提取出来，以减少冗余：

this.pWorkOrder.checkRequirements = this.description;

然后可以使用 switch 语句来替换多个 if 语句：

switch(this.pWorkOrder.orderState) {
  case '20':
  case '30':
  case '50':
    this.pWorkOrder.checkRequirements = this.description;
    break;
  case '40':
    if (this.pictureDet.length <= 0) {
      this.$tip.error(`${this.popupSitch.image.label}必填`);
      return;
    }
    this.pWorkOrder.checkRequirements = this.description;
    this.pWorkOrder.mPicture = this.pictureDet.join(',');
    break;
  default:
    break;
}

这样代码就更简洁易读了。

相关问题

帮我优化这段代码 handleWorkOrderMessage() { // 待办理、待审核二级弹窗 console.log(this.pWorkOrder.orderState); if (this.pWorkOrder.orderState === '20') { this.popupSitch.description.show = true; this.popupSitch.description.label = '经办意见'; this.description = '按要求完成，下单！'; } // 接单 if (this.pWorkOrder.orderState === '30') { this.popupSitch.description.show = true; this.popupSitch.description.label = '经办意见'; this.description = '按要求完成，接单！'; } // 反馈 if (this.pWorkOrder.orderState === '40') { this.popupSitch.description.show = true; this.popupSitch.description.label = '经办意见'; this.popupSitch.image.label = '反馈图片'; this.popupSitch.image.show = true; this.description = '按要求完成，反馈！'; } // 审核关闭 if (this.pWorkOrder.orderState === '50') { this.popupSitch.description.show = true; this.popupSitch.description.label = '经办意见'; this.description = '按要求完成，审核关闭！'; } this.$refs.orderPopup.open(); },

可以尝试以下优化：

1. 将重复的代码提取出来，避免重复写相同的语句。例如，多个条件下都需要设置 `popupSitch.description.show` 为 `true`，可以在代码开头先设置为 `false`，然后根据条件进行修改。

2. 使用 switch 语句替代多个 if 语句，可以让代码更加清晰易懂。

3. 如果有多处使用的字符串，可以将其提取为常量或者变量，方便修改和管理。

下面是优化后的代码示例：

handleWorkOrderMessage() {
  const DES_LABEL = '经办意见';
  const DESC_COMPLETE = '按要求完成，';
  const DESC_ORDER = '下单！';
  const DESC_ACCEPT = '接单！';
  const DESC_FEEDBACK = '反馈！';
  const DESC_CLOSE = '审核关闭！';

  this.popupSitch = {
    description: {
      show: false,
      label: ''
    },
    image: {
      show: false,
      label: ''
    }
  };

  switch (this.pWorkOrder.orderState) {
    case '20':
      this.popupSitch.description.show = true;
      this.popupSitch.description.label = DES_LABEL;
      this.description = DESC_COMPLETE + DESC_ORDER;
      break;
    case '30':
      this.popupSitch.description.show = true;
      this.popupSitch.description.label = DES_LABEL;
      this.description = DESC_COMPLETE + DESC_ACCEPT;
      break;
    case '40':
      this.popupSitch.description.show = true;
      this.popupSitch.description.label = DES_LABEL;
      this.popupSitch.image.show = true;
      this.popupSitch.image.label = '反馈图片';
      this.description = DESC_COMPLETE + DESC_FEEDBACK;
      break;
    case '50':
      this.popupSitch.description.show = true;
      this.popupSitch.description.label = DES_LABEL;
      this.description = DESC_COMPLETE + DESC_CLOSE;
      break;
    default:
      break;
  }

  this.$refs.orderPopup.open();
},

v-if="scope.row.checkInState==='待入住'"怎么同时判断scope.row.orderState==='已支付'

你可以使用逻辑运算符 &&（与）来同时判断两个条件，将它们放在同一个v-if指令中即可，示例代码如下：

v-if="scope.row.checkInState==='待入住' && scope.row.orderState==='已支付'"

这样，只有当两个条件都满足时，才会渲染指定的元素。