SyntaxError: Unexpected token e in JSON at position 248

This error occurs when there is a syntax error in a JSON string. The error message is indicating that there is an unexpected character "e" at position 248.

To fix this error, you need to locate the JSON string in your code and carefully examine it to find where the error is occurring. Check for any missing or extra commas, brackets, or quotes.

Once you have found and fixed the error, the JSON string should be valid and the error should be resolved.

相关问题

SyntaxError: Unexpected token 故 in JSON at position

SyntaxError: Unexpected token 故 in JSON at position 是由于JSON解析失败导致的。通常情况下，这种错误是因为传递给JSON.parse()函数的字符串不符合JSON格式所致。可能原因包括：字符串中存在非法的字符，字符串格式不完整或缺失引号等。解决此问题的方法是确保你传递给JSON.parse()函数的字符串是有效的JSON格式。你可以使用isJson()方法来检查字符串是否是有效的JSON格式，如果不是，则需要对字符串进行修复或检查传递给JSON.parse()函数的参数。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
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SyntaxError: Unexpected token < in JSON at position 0

"SyntaxError: Unexpected token < in JSON at position 0"这个错误通常是由于尝试将非JSON格式的数据解析为JSON对象而引起的。在这种情况下，解析器在遇到无效的JSON标记时会抛出此错误。常见的原因是尝试将包含HTML标签或其他非法字符的字符串解析为JSON对象。
要解决这个问题，你可以使用try-catch语句来捕获异常，并在解析之前确保你的字符串是有效的JSON格式。你可以使用JSON.parse()方法将字符串解析为JSON对象之前，先使用合适的方法来验证字符串是否是有效的JSON格式。
以下是一种判断字符串是否是有效的JSON格式的方法：

function isJson(str) {
  try {
    JSON.parse(str);
  } catch (e) {
    return false;
  }
  return true;
}

你可以在调用JSON.parse()之前使用isJson()方法来验证字符串是否是有效的JSON格式。如果返回true，说明字符串是有效的JSON格式，可以进行解析；如果返回false，则说明字符串不是有效的JSON格式，需要进行相应的处理。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
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