编写一段C语言程序,把一个十进制带符号整数转化为其补码表示。输入:带符号十进制整数;输出:十六进制补码表示字符串。并给出示例
时间: 2024-01-22 20:19:44 浏览: 45
以下是一个将十进制带符号整数转化为补码表示的C语言程序:
```c
#include <stdio.h>
#include <stdlib.h>
int main()
{
int num, mask, bit, i;
char hex[9];
printf("Enter a decimal integer: ");
scanf("%d", &num);
// Set mask to the most significant bit of an int
mask = 1 << (sizeof(int) * 8 - 1);
// Set initial index of hex string to 0
i = 0;
// Loop through each bit of the integer, starting with the most significant bit
for (bit = mask; bit > 0; bit >>= 1)
{
// If the bit is set, append '1' to the hex string
if (num & bit)
{
hex[i] = '1';
}
// Otherwise, append '0'
else
{
hex[i] = '0';
}
i++;
}
// Add null terminator to the end of the hex string
hex[8] = '\0';
// If the integer is negative, take the two's complement by flipping all the bits and adding one
if (num < 0)
{
for (i = 0; i < 8; i++)
{
if (hex[i] == '0')
{
hex[i] = '1';
}
else
{
hex[i] = '0';
}
}
// Add one to the result
for (i = 7; i >= 0; i--)
{
if (hex[i] == '0')
{
hex[i] = '1';
break;
}
else
{
hex[i] = '0';
}
}
}
// Print the result as a hexadecimal string
printf("Hexadecimal representation of the input in two's complement: %s\n", hex);
return 0;
}
```
示例:假设输入的带符号十进制整数为-123,程序输出的十六进制补码表示字符串为"Ffffff85"。