解释 System.out.println("jwtToken in MyInterceptor "+jwtTokenUtil); System.out.println("username= "+jwtTokenUtil.getUsernameFromToken(token));
时间: 2024-03-19 21:40:17 浏览: 24
这段代码是用于在控制台输出一些信息。在第一行中,使用了System.out.println()方法将一个字符串和变量jwtTokenUtil打印出来,其中字符串"jwtToken in MyInterceptor "是固定的,而变量jwtTokenUtil的值会在这段代码被执行时被替换为实际的jwtTokenUtil对象。第二行同样使用了System.out.println()方法,将一个字符串"username= "和从jwtTokenUtil对象中解析出来的token中的用户名打印出来。这个用户名是通过调用jwtTokenUtil对象的getUsernameFromToken()方法获取的。整个代码的作用是在控制台输出一些调试信息,帮助开发人员理解代码的执行过程和结果。
相关问题
System.out.println('1' + 1 + 1);
This code will not compile because it contains an invalid syntax. The correct syntax for the System.out.println() method in Java requires a string or expression to be passed as an argument within the parentheses. Therefore, the code should be modified to something like:
System.out.println("1" + 1 + 1);
This will concatenate the string "1" with the integers 1 and 1, resulting in the output "111".
System.out.println("13" + 5 + 3);
This code will result in a compilation error because there are no commas separating the three arguments in the println method. It should be written as:
System.out.println("13" + 5 + 3);
This will output the string "135" because the + operator is used for concatenation when at least one operand is a string.