python单机小游戏贪吃蛇并加上注释

好的，下面是带有注释的Python单机小游戏贪吃蛇的实现过程：

# 导入必要的模块
import pygame
import random

# 初始化Pygame
pygame.init()

# 设置游戏窗口大小和标题
window_width = 640
window_height = 480
game_window = pygame.display.set_mode((window_width, window_height))
pygame.display.set_caption('Snake Game')

# 定义颜色和字体
white = (255, 255, 255)
black = (0, 0, 0)
red = (255, 0, 0)
font = pygame.font.SysFont(None, 25)

# 定义贪吃蛇和食物的初始位置和大小
block_size = 10
snake_speed = 15

# 定义绘制贪吃蛇的函数
def snake(snake_list, block_size):
    for x_y in snake_list:
        pygame.draw.rect(game_window, black, [x_y[0], x_y[1], block_size, block_size])

# 定义显示文字的函数
def message_to_screen(msg, color):
    screen_text = font.render(msg, True, color)
    game_window.blit(screen_text, [window_width/6, window_height/6])

# 定义游戏主函数
def gameLoop():
    # 定义游戏结束和退出的标志
    game_exit = False
    game_over = False

    # 定义贪吃蛇头的位置和移动的速度
    lead_x = window_width/2
    lead_y = window_height/2
    lead_x_change = 0
    lead_y_change = 0

    # 定义贪吃蛇的列表和长度
    snake_list = []
    snake_length = 1

    # 定义食物的位置
    food_x = round(random.randrange(0, window_width-block_size)/10.0)*10.0
    food_y = round(random.randrange(0, window_height-block_size)/10.0)*10.0

    # 开始游戏循环
    while not game_exit:
        # 如果游戏结束，显示游戏结束的文字
        while game_over == True:
            game_window.fill(white)
            message_to_screen('Game over, press Q to quit or C to play again', red)
            pygame.display.update()

            # 处理游戏结束后的事件
            for event in pygame.event.get():
                if event.type == pygame.KEYDOWN:
                    if event.key == pygame.K_q:
                        game_exit = True
                        game_over = False
                    elif event.key == pygame.K_c:
                        gameLoop()

        # 处理游戏中的事件
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                game_exit = True
            if event.type == pygame.KEYDOWN:
                if event.key == pygame.K_LEFT:
                    lead_x_change = -block_size
                    lead_y_change = 0
                elif event.key == pygame.K_RIGHT:
                    lead_x_change = block_size
                    lead_y_change = 0
                elif event.key == pygame.K_UP:
                    lead_y_change = -block_size
                    lead_x_change = 0
                elif event.key == pygame.K_DOWN:
                    lead_y_change = block_size
                    lead_x_change = 0

        # 判断贪吃蛇是否撞墙，如果是，游戏结束
        if lead_x >= window_width or lead_x < 0 or lead_y >= window_height or lead_y < 0:
            game_over = True

        # 计算贪吃蛇头的位置
        lead_x += lead_x_change
        lead_y += lead_y_change

        # 在游戏窗口中绘制食物和贪吃蛇
        game_window.fill(white)
        pygame.draw.rect(game_window, red, [food_x, food_y, block_size, block_size])

        snake_head = []
        snake_head.append(lead_x)
        snake_head.append(lead_y)
        snake_list.append(snake_head)

        if len(snake_list) > snake_length:
            del snake_list[0]

        for each_segment in snake_list[:-1]:
            if each_segment == snake_head:
                game_over = True

        snake(snake_list, block_size)

        pygame.display.update()

        # 判断贪吃蛇是否吃到了食物，如果是，增加贪吃蛇的长度
        if lead_x == food_x and lead_y == food_y:
            food_x = round(random.randrange(0, window_width-block_size)/10.0)*10.0
            food_y = round(random.randrange(0, window_height-block_size)/10.0)*10.0
            snake_length += 1

        # 控制游戏的速度
        clock.tick(snake_speed)

    # 退出Pygame
    pygame.quit()
    quit()

# 调用游戏主函数
gameLoop()

这样一个带有注释的Python单机小游戏贪吃蛇就完成了。希望对您有所帮助！