这段代码报KeyError错误,该如何修改:def oddString(self, words: List[str]) -> str: n = len(words) dic = {} ans = 0 for i in range(0, n): len_word = len(words[i]) diff = [ord(words[i][j]) - ord(words[i][j-1]) for j in range(1, len_word)] if tuple(diff) in dic.keys(): dic[tuple(diff)] = 0 else: dic[tuple(diff)] += 1 if dic[tuple(diff)] == 1: ans = 1 return words[ans]
时间: 2024-01-02 19:04:57 浏览: 106
这段代码会报KeyError错误,是因为在if条件语句中,当dic字典中不存在tuple(diff)这个键时,会执行dic[tuple(diff)] += 1语句,但是此时dic字典中并没有tuple(diff)这个键,所以会报KeyError错误。
为了避免这个错误,可以在if条件语句前先判断一下tuple(diff)是否已经在字典中存在,如果不存在,就先将其添加到字典中,然后再执行后面的代码。修改后的代码如下:
```
def oddString(self, words: List[str]) -> str:
n = len(words)
dic = {}
ans = 0
for i in range(0, n):
len_word = len(words[i])
diff = [ord(words[i][j]) - ord(words[i][j-1]) for j in range(1, len_word)]
if tuple(diff) not in dic:
dic[tuple(diff)] = 0
if dic[tuple(diff)] == 0:
ans = i
dic[tuple(diff)] += 1
return words[ans]
```
这里将if条件语句中的dic[tuple(diff)] == 1改为了dic[tuple(diff)] == 0,同时将ans的初始值改为0,这样就可以正确地找到奇异字符串了。
阅读全文