操作系统银行家算法c语言代码

下面是一个简单的银行家算法的C语言代码实现：

#include <stdio.h>
#include <stdbool.h>

#define MAX_PROCESS_NUM 10
#define MAX_RESOURCE_NUM 10

int available[MAX_RESOURCE_NUM] = {0};
int max[MAX_PROCESS_NUM][MAX_RESOURCE_NUM] = {0};
int allocation[MAX_PROCESS_NUM][MAX_RESOURCE_NUM] = {0};
int need[MAX_PROCESS_NUM][MAX_RESOURCE_NUM] = {0};
bool finish[MAX_PROCESS_NUM] = {false};
int safe_sequence[MAX_PROCESS_NUM] = {0};

int process_num, resource_num;

bool safety_check() {
    int work[MAX_RESOURCE_NUM];
    bool finish_copy[MAX_PROCESS_NUM];
    for (int i = 0; i < resource_num; i++) {
        work[i] = available[i];
    }
    for (int i = 0; i < process_num; i++) {
        finish_copy[i] = finish[i];
    }
    int count = 0;
    while (count < process_num) {
        bool found = false;
        for (int i = 0; i < process_num; i++) {
            if (!finish_copy[i]) {
                bool enough = true;
                for (int j = 0; j < resource_num; j++) {
                    if (need[i][j] > work[j]) {
                        enough = false;
                        break;
                    }
                }
                if (enough) {
                    found = true;
                    for (int j = 0; j < resource_num; j++) {
                        work[j] += allocation[i][j];
                    }
                    finish_copy[i] = true;
                    safe_sequence[count] = i;
                    count++;
                }
            }
        }
        if (!found) {
            return false;
        }
    }
    return true;
}

int main() {
    printf("Enter the number of processes: ");
    scanf("%d", &process_num);
    printf("Enter the number of resources: ");
    scanf("%d", &resource_num);
    printf("Enter the available amount of each resource:\n");
    for (int i = 0; i < resource_num; i++) {
        scanf("%d", &available[i]);
    }
    printf("Enter the maximum demand of each process:\n");
    for (int i = 0; i < process_num; i++) {
        for (int j = 0; j < resource_num; j++) {
            scanf("%d", &max[i][j]);
        }
    }
    printf("Enter the amount of each resource currently allocated to each process:\n");
    for (int i = 0; i < process_num; i++) {
        for (int j = 0; j < resource_num; j++) {
            scanf("%d", &allocation[i][j]);
            need[i][j] = max[i][j] - allocation[i][j];
        }
    }
    if (safety_check()) {
        printf("Safe sequence:");
        for (int i = 0; i < process_num; i++) {
            printf(" P%d", safe_sequence[i]);
        }
        printf("\n");
    } else {
        printf("Unsafe state detected.\n");
    }
    return 0;
}

注意：本代码实现仅供参考，实际应用中需要根据具体情况进行修改和完善。