用C语言编程实现两个数组中对应该元素值的交换(数组的长度定义成5)。
时间: 2023-08-14 20:04:34 浏览: 37
好的,下面是代码实现:
```c
#include <stdio.h>
void swap(int arr1[], int arr2[], int len) {
int temp;
for (int i = 0; i < len; i++) {
temp = arr1[i];
arr1[i] = arr2[i];
arr2[i] = temp;
}
}
int main() {
int arr1[5] = {1, 2, 3, 4, 5};
int arr2[5] = {6, 7, 8, 9, 10};
printf("交换前:\n");
for (int i = 0; i < 5; i++) {
printf("%d ", arr1[i]);
}
printf("\n");
for (int i = 0; i < 5; i++) {
printf("%d ", arr2[i]);
}
printf("\n");
swap(arr1, arr2, 5);
printf("交换后:\n");
for (int i = 0; i < 5; i++) {
printf("%d ", arr1[i]);
}
printf("\n");
for (int i = 0; i < 5; i++) {
printf("%d ", arr2[i]);
}
printf("\n");
return 0;
}
```
输出结果:
```
交换前:
1 2 3 4 5
6 7 8 9 10
交换后:
6 7 8 9 10
1 2 3 4 5
```