python中 根结点是declarations 第二层节点是type type 节点下有field和typeref 两个节点,现在是按type节点分块获取每块里面的内容,并将获取的内容按type节点值排序,葱从A- Z依次排序
时间: 2024-02-01 14:13:16 浏览: 24
可以使用Python中的xml.etree.ElementTree模块来解析XML文件,并按照要求对type节点里的内容进行排序。
具体操作步骤如下:
1. 导入xml.etree.ElementTree模块
```python
import xml.etree.ElementTree as ET
```
2. 使用ElementTree.parse()方法解析XML文件
```python
tree = ET.parse('your_xml_file.xml')
```
3. 获取根节点
```python
root = tree.getroot()
```
4. 遍历根节点下的所有type节点,并将每个type节点的内容放入对应的列表中
```python
type_dict = {}
for type_node in root.findall('./declarations/type'):
type_name = type_node.get('id')
type_content = ET.tostring(type_node, encoding='unicode')
if type_name not in type_dict:
type_dict[type_name] = []
type_dict[type_name].append(type_content)
```
5. 对每个type节点的内容列表按照type节点名称排序,并按照A-Z的顺序依次输出
```python
sorted_type_names = sorted(type_dict.keys())
for type_name in sorted_type_names:
sorted_type_contents = sorted(type_dict[type_name])
for type_content in sorted_type_contents:
print(type_content)
```
完整代码示例:
```python
import xml.etree.ElementTree as ET
tree = ET.parse('your_xml_file.xml')
root = tree.getroot()
type_dict = {}
for type_node in root.findall('./declarations/type'):
type_name = type_node.get('id')
type_content = ET.tostring(type_node, encoding='unicode')
if type_name not in type_dict:
type_dict[type_name] = []
type_dict[type_name].append(type_content)
sorted_type_names = sorted(type_dict.keys())
for type_name in sorted_type_names:
sorted_type_contents = sorted(type_dict[type_name])
for type_content in sorted_type_contents:
print(type_content)
```