大转盘抽奖java实现

好的，以下是一个简单的大转盘抽奖的 Java 实现：

import java.util.Random;

public class LuckyDraw {
    private static final String[] PRIZES = {"一等奖", "二等奖", "三等奖", "四等奖", "五等奖", "六等奖", "七等奖", "八等奖", "谢谢参与"};
    private static final int[] PROBABILITIES = {1, 2, 3, 4, 5, 6, 7, 8, 100};
    private static final int TOTAL_PROBABILITY = 128;

    public static void main(String[] args) {
        int luckyNumber = new Random().nextInt(TOTAL_PROBABILITY);
        int cumulativeProbability = 0;
        int prizeIndex = 0;

        for (int i = 0; i < PROBABILITIES.length; i++) {
            cumulativeProbability += PROBABILITIES[i];
            if (luckyNumber < cumulativeProbability) {
                prizeIndex = i;
                break;
            }
        }

        System.out.println("您抽中的奖品是：" + PRIZES[prizeIndex]);
    }
}

以上代码中，定义了奖品数组 `PRIZES` 和概率数组 `PROBABILITIES`，并且定义了总概率 `TOTAL_PROBABILITY`。通过 `Random` 类生成一个随机数作为抽奖的幸运数字，然后逐一累加每个奖品的概率，如果幸运数字小于当前累加概率，则抽中该奖品。最后输出抽中的奖品名称即可。