在quartus中用74161实现模28计数器
时间: 2023-12-06 19:02:06 浏览: 107
在Quartus II中使用74161实现模28计数器的步骤如下:
1. 打开Quartus II软件,创建一个新工程。
2. 在“File”菜单中选择“New”,创建一个新的VHDL文件。
3. 在VHDL文件中,定义输入输出端口和内部信号:
```vhdl
entity counter_28 is
Port ( clk : in STD_LOGIC; -- 时钟信号
reset : in STD_LOGIC; -- 复位信号
count_out : out STD_LOGIC_VECTOR (4 downto 0)); -- 输出计数值
end counter_28;
architecture Behavioral of counter_28 is
signal counter : std_logic_vector(4 downto 0); -- 内部计数器
begin
```
4. 在内部信号中定义一个5位二进制计数器,使用74161实现:
```vhdl
process(clk, reset)
begin
if reset = '1' then -- 复位计数器
counter <= "00000";
elsif rising_edge(clk) then -- 时钟上升沿触发
if counter = "11111" then -- 判断是否到达最大值,需要复位
counter <= "00000";
else
counter <= counter + 1; -- 计数器加1
end if;
end if;
end process;
```
5. 将最高位的输出引脚Q4连接到最低位的输入引脚CP,形成一个环形计数器:
```vhdl
process(clk, reset)
begin
if reset = '1' then -- 复位计数器
counter <= "00000";
elsif rising_edge(clk) then -- 时钟上升沿触发
if counter = "11111" then -- 判断是否到达最大值,需要复位
counter <= "00000";
else
counter <= counter + 1; -- 计数器加1
end if;
end if;
end process;
process(counter)
begin
case counter(3 downto 0) is
when "0000" => count_out <= "00000"; -- 输出0
when "0001" => count_out <= "00001"; -- 输出1
when "0010" => count_out <= "00010"; -- 输出2
when "0011" => count_out <= "00011"; -- 输出3
when "0100" => count_out <= "00100"; -- 输出4
when "0101" => count_out <= "00101"; -- 输出5
when "0110" => count_out <= "00110"; -- 输出6
when "0111" => count_out <= "00111"; -- 输出7
when "1000" => count_out <= "01000"; -- 输出8
when "1001" => count_out <= "01001"; -- 输出9
when "1010" => count_out <= "01010"; -- 输出10
when "1011" => count_out <= "01011"; -- 输出11
when "1100" => count_out <= "01100"; -- 输出12
when "1101" => count_out <= "01101"; -- 输出13
when "1110" => count_out <= "01110"; -- 输出14
when "1111" => count_out <= "01111"; -- 输出15
end case;
count_out(4) <= counter(4); -- 最高位输出
end process;
```
6. 在仿真中测试代码,确保计数器正常工作。
7. 在Quartus中生成并下载到FPGA板子上,测试计数器是否正常工作。
需要注意的是,以上代码仅实现了简单的模28计数器,实际应用中可能需要进一步的优化和改进。
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