创建了一个员工信息数据库,创建了一个部门信息表,创建了一个员工信息表,列出在部门sales工作的员工的姓名,假定不知道销售部的部门编号。
时间: 2023-11-22 07:52:41 浏览: 120
假设部门信息表名为"departments",员工信息表名为"employees",其中员工信息表中有一个"department_id"列用于表示员工所在的部门编号。
您可以使用以下SQL查询来列出在销售部门工作的员工姓名:
```
SELECT employees.employee_name
FROM employees
INNER JOIN departments ON employees.department_id = departments.department_id
WHERE departments.department_name = 'sales';
```
这个查询语句使用了INNER JOIN将两个表连接起来,然后使用WHERE子句来限制只查询部门名称为"sales"的员工信息。最后,SELECT子句只选择了员工姓名这一列。
相关问题
,编写Python代码,完成下述嵌入式SQL的查询要求。 0.创建企业人事数据库1. 列出至少有四个员工的所有部门信息。 2. 列出所有员工的姓名及其直接上级的姓名,没有领导的雇员也列出。 3. 列出受雇日期早于其直接上级的所有员工编号/姓名/部门名称。 4. 列出最低薪金大于1500的各种工作及此从事此工作的全部雇员人数。 5. 列出在部门sales工作的员工的姓名,假定不知道销售部的部门编号。
```python
# 导入必要的模块
import sqlite3
# 连接数据库
conn = sqlite3.connect('company.db')
cursor = conn.cursor()
# 创建表
cursor.execute('''
CREATE TABLE IF NOT EXISTS department (
dept_no TEXT PRIMARY KEY,
dept_name TEXT NOT NULL,
location TEXT
)
''')
cursor.execute('''
CREATE TABLE IF NOT EXISTS employee (
emp_no INTEGER PRIMARY KEY,
emp_name TEXT NOT NULL,
job TEXT NOT NULL,
mgr_no INTEGER,
hire_date DATE NOT NULL,
salary INTEGER NOT NULL,
dept_no TEXT NOT NULL,
FOREIGN KEY (dept_no) REFERENCES department(dept_no),
FOREIGN KEY (mgr_no) REFERENCES employee(emp_no)
)
''')
# 插入数据
cursor.execute("INSERT INTO department VALUES ('d001', 'Marketing', 'Tokyo')")
cursor.execute("INSERT INTO department VALUES ('d002', 'Finance', 'Osaka')")
cursor.execute("INSERT INTO department VALUES ('d003', 'Sales', 'Kyoto')")
cursor.execute("INSERT INTO department VALUES ('d004', 'IT', 'Tokyo')")
cursor.execute("INSERT INTO employee VALUES (1001, 'John', 'Manager', NULL, '2000-01-01', 3000, 'd001')")
cursor.execute("INSERT INTO employee VALUES (1002, 'Mary', 'Manager', NULL, '2001-01-01', 4000, 'd002')")
cursor.execute("INSERT INTO employee VALUES (1003, 'Tom', 'Salesman', 1001, '2002-01-01', 2000, 'd001')")
cursor.execute("INSERT INTO employee VALUES (1004, 'Jane', 'Clerk', 1001, '2003-01-01', 1500, 'd001')")
cursor.execute("INSERT INTO employee VALUES (1005, 'Peter', 'Salesman', 1001, '2004-01-01', 2500, 'd001')")
cursor.execute("INSERT INTO employee VALUES (1006, 'David', 'Clerk', 1002, '2005-01-01', 1200, 'd002')")
cursor.execute("INSERT INTO employee VALUES (1007, 'Lucy', 'Clerk', 1002, '2006-01-01', 1300, 'd002')")
cursor.execute("INSERT INTO employee VALUES (1008, 'Jack', 'Programmer', 1002, '2007-01-01', 2000, 'd004')")
cursor.execute("INSERT INTO employee VALUES (1009, 'Rose', 'Manager', 1001, '2008-01-01', 5000, 'd003')")
cursor.execute("INSERT INTO employee VALUES (1010, 'Bob', 'Salesman', 1009, '2009-01-01', 1800, 'd003')")
cursor.execute("INSERT INTO employee VALUES (1011, 'Judy', 'Salesman', 1009, '2010-01-01', 1900, 'd003')")
cursor.execute("INSERT INTO employee VALUES (1012, 'Mike', 'Clerk', 1009, '2011-01-01', 1400, 'd003')")
# 提交更改
conn.commit()
# 查询要求1
cursor.execute('''
SELECT department.dept_name, COUNT(employee.emp_no) AS num_of_employees
FROM department JOIN employee ON department.dept_no = employee.dept_no
GROUP BY department.dept_name
HAVING COUNT(employee.emp_no) >= 4
''')
print("At least 4 employees in each department:")
for row in cursor.fetchall():
print(row)
# 查询要求2
cursor.execute('''
SELECT e1.emp_name, e2.emp_name AS manager_name
FROM employee e1 LEFT JOIN employee e2 ON e1.mgr_no = e2.emp_no
''')
print("Employee names and their managers' names:")
for row in cursor.fetchall():
print(row)
# 查询要求3
cursor.execute('''
SELECT e1.emp_no, e1.emp_name, d1.dept_name
FROM employee e1 JOIN employee e2 ON e1.mgr_no = e2.emp_no
JOIN department d1 ON e1.dept_no = d1.dept_no
WHERE e1.hire_date < e2.hire_date
''')
print("Employees hired before their managers:")
for row in cursor.fetchall():
print(row)
# 查询要求4
cursor.execute('''
SELECT job, COUNT(emp_no) AS num_of_employees
FROM employee
GROUP BY job
HAVING MIN(salary) > 1500
''')
print("Jobs with minimum salary > 1500 and the number of employees in the job:")
for row in cursor.fetchall():
print(row)
# 查询要求5
cursor.execute('''
SELECT emp_name
FROM employee JOIN department ON employee.dept_no = department.dept_no
WHERE dept_name = 'Sales'
''')
print("Employee names who work in the sales department:")
for row in cursor.fetchall():
print(row)
# 关闭连接
conn.close()
```
emp员工表(empno员工号/ename员工姓名job工作/mgr上级编号/hiredate受雇日期/sal薪金/comm 佣金/deptno部门编号) dept部门表(deptno部门编号/dname部门名称/oc 地点) 工资=薪金+佣金 问题: 1.列出至少有一个员工的所有部门(3分) 2.列出薪金比“SMITH°多的所有员工。(3分) 3. 列出所有员工的姓名及其直接上级的姓名。 (3}) 4. 列出受雇日期晚于其直接上级的所有员工。 (3分) 5.列出部门名称和这些部门的员工信息,同时列出那些没有员工的部门。(3分) 6. 列出所有“CLERK”(办事员)的姓名及其部门名称。(3分) 7.列出最低薪金大于1500的各种工作。(3分) 8.列出在部门“SALES°’(销售部) 工作的员工的姓名,假定不知道销售部的部门编号。(4分) 9.列出薪金高于公司平均薪金的所有员工。(4 分) 10.列出与“SCOTT”从事相同工作的所有员工。(4分) 11. 列出薪金等于部门30中员工的薪金的所有员工的姓名和薪金。(4分) 12.列出薪金高于在部门30工作的所有员工的薪金的员工姓名和薪金。(4分) 13.列出在每个部门工作的员工数量、平均工资和平均服务期限。(4分) 14. 列出所有员工的姓名、部门名称和工资。 (5分) 15. 列出所有部门的详细信息和部门人数。(5 分) 16. 列出各种工作的最低工资。(5分) 17.列出MANAGER(经理)的最低薪金。(5 分) 18.列出所有员工的年工资,按年薪从低到高排序。(5分)
抱歉,作为一个语言模型,我没有办法直接执行数据库查询,但我可以提供基于 SQL 语句的答案供您参考。
1. 列出至少有一个员工的所有部门:
```sql
SELECT DISTINCT d.dname
FROM emp e, dept d
WHERE e.deptno = d.deptno;
```
2. 列出薪金比“SMITH”多的所有员工:
```sql
SELECT e.ename, e.sal
FROM emp e, emp s
WHERE e.sal > s.sal AND s.ename = 'SMITH';
```
3. 列出所有员工的姓名及其直接上级的姓名:
```sql
SELECT e.ename, m.ename
FROM emp e LEFT JOIN emp m ON e.mgr = m.empno;
```
4. 列出受雇日期晚于其直接上级的所有员工:
```sql
SELECT e.ename, e.hiredate, m.ename, m.hiredate
FROM emp e, emp m
WHERE e.mgr = m.empno AND e.hiredate > m.hiredate;
```
5. 列出部门名称和这些部门的员工信息,同时列出那些没有员工的部门:
```sql
SELECT d.dname, e.ename, e.job, e.hiredate, e.sal, e.comm
FROM dept d LEFT JOIN emp e ON d.deptno = e.deptno
ORDER BY d.dname;
```
6. 列出所有“CLERK”(办事员)的姓名及其部门名称:
```sql
SELECT e.ename, d.dname
FROM emp e, dept d
WHERE e.deptno = d.deptno AND e.job = 'CLERK';
```
7. 列出最低薪金大于1500的各种工作:
```sql
SELECT DISTINCT e.job
FROM emp e
WHERE e.sal > 1500
ORDER BY e.job;
```
8. 列出在部门“SALES”(销售部)工作的员工的姓名,假定不知道销售部的部门编号:
```sql
SELECT e.ename
FROM emp e, dept d
WHERE e.deptno = d.deptno AND d.dname = 'SALES';
```
9. 列出薪金高于公司平均薪金的所有员工:
```sql
SELECT e.ename, e.sal
FROM emp e
WHERE e.sal > (SELECT AVG(sal) FROM emp);
```
10. 列出与“SCOTT”从事相同工作的所有员工:
```sql
SELECT e.ename, e.job
FROM emp e, emp s
WHERE e.job = s.job AND s.ename = 'SCOTT' AND e.ename <> 'SCOTT';
```
11. 列出薪金等于部门30中员工的薪金的所有员工的姓名和薪金:
```sql
SELECT e.ename, e.sal
FROM emp e
WHERE e.sal = (SELECT sal FROM emp WHERE deptno = 30);
```
12. 列出薪金高于在部门30工作的所有员工的薪金的员工姓名和薪金:
```sql
SELECT e.ename, e.sal
FROM emp e
WHERE e.sal > (SELECT MAX(sal) FROM emp WHERE deptno = 30);
```
13. 列出在每个部门工作的员工数量、平均工资和平均服务期限:
```sql
SELECT d.dname, COUNT(e.empno) AS num_of_emp, AVG(e.sal) AS avg_sal, AVG(MONTHS_BETWEEN(SYSDATE, e.hiredate)/12) AS avg_service_years
FROM dept d LEFT JOIN emp e ON d.deptno = e.deptno
GROUP BY d.dname;
```
14. 列出所有员工的姓名、部门名称和工资:
```sql
SELECT e.ename, d.dname, e.sal
FROM emp e, dept d
WHERE e.deptno = d.deptno;
```
15. 列出所有部门的详细信息和部门人数:
```sql
SELECT d.dname, d.oc, COUNT(e.empno) AS num_of_emp
FROM dept d LEFT JOIN emp e ON d.deptno = e.deptno
GROUP BY d.dname, d.oc;
```
16. 列出各种工作的最低工资:
```sql
SELECT e.job, MIN(e.sal) AS min_sal
FROM emp e
GROUP BY e.job;
```
17. 列出MANAGER(经理)的最低薪金:
```sql
SELECT MIN(e.sal) AS min_sal
FROM emp e, emp m
WHERE e.mgr = m.empno AND m.job = 'MANAGER';
```
18. 列出所有员工的年工资,按年薪从低到高排序:
```sql
SELECT e.ename, e.sal*12 AS annual_sal
FROM emp e
ORDER BY annual_sal;
```
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