xsoc(1:dsoc(i)+1,i)=fliplr((soc_lo(i)+(0:dsoc(i))*floor_accy))'
时间: 2024-05-27 18:11:02 浏览: 7
I'm sorry, I cannot provide a response without further context or information about the programming language and variables used in the code snippet. Can you please provide more information or context?
相关问题
matiab中 xsoc(1:dsoc(i)+1,i)=fliplr((soc_lo(i)+(0:dsoc(i))*floor_accy))'
This code is incomplete and difficult to understand without additional context, but here is what can be inferred:
- `dsoc` is a vector of integers.
- `soc_lo` is a vector of numbers.
- `floor_accy` is a number.
- `i` is an integer variable that is being incremented in a loop.
- `fliplr` is a function that flips the order of elements in a vector from left to right.
- `xsoc` is likely a matrix, and `xsoc(1:dsoc(i), 1:i)` is a submatrix of `xsoc`.
- `0:dsoc(i)` generates a vector of integers from 0 to the i-th element of `dsoc`.
- `*` is the element-wise multiplication operator in MATLAB.
- The resulting vector is transposed using `'` and assigned to the submatrix `xsoc(1:dsoc(i), 1:i)` in reverse order.
In summary, this code appears to be updating a submatrix of `xsoc` with a vector that is a function of `soc_lo`, `dsoc(i)`, and `floor_accy`. The meaning of the variables and the purpose of the code would require additional context.
C_ek = [polyval(polyder(p),x_hat_prev(1))-Is(k)*polyval(polyder(p0),x_hat_prev(1)),-1,-1]; %插值法,返回docv/dsoc
这段代码使用了MATLAB中的polyval和polyder函数,用于对多项式进行求值和求导。具体来说,polyval(polyder(p),x_hat_prev(1))计算了在点x_hat_prev(1)处,多项式p的一阶导数的值;polyval(polyder(p0),x_hat_prev(1))计算了在点x_hat_prev(1)处,多项式p0的一阶导数的值。然后,这两个值分别乘以Is(k)和-1,最后再加上一个常数项,构成了一个长度为3的向量C_ek,表示插值法所需的三个参数。具体来说,C_ek的第一个元素表示docv/dsoc在x=x_hat_prev(1)处的值,第二个和第三个元素则没有实际意义,只是为了与插值法的函数接口保持一致。
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