async changeSelectPosition (item: any) { console.log(this.formEntity.DrillOrgIDarr, 'this.formEntity.DrillOrgIDarr') let checkResult if(this.formEntity.ExamType==0){ checkResult = this.checktypetask(this.formEntity.ExamType, this.formEntity.DrillOrgIDarr, item.value[0].ID) }else{ checkResult = this.checktypetask(this.formEntity.ExamType, this.formEntity.ByCheckOrgIDs, item.value[0].ID) } if(checkResult){ this.formEntity.PostName = item.value[0].text this.formEntity.PostId = item.value[0].ID this.showPosition = false }else{ return } },我已经这么做了，他还是会进行if里的赋值操作

原因是 `checktypetask` 函数是异步函数，执行完异步操作后才返回结果，而在 `changeSelectPosition` 函数中，没有等待 `checktypetask` 函数执行完毕，就直接进行了赋值操作，因此无法正确处理返回值。

你可以在 `changeSelectPosition` 函数中加上 `await`，等待 `checktypetask` 函数执行完毕并返回结果后，再进行赋值操作，例如：

async changeSelectPosition(item: any) {
  console.log(this.formEntity.DrillOrgIDarr, 'this.formEntity.DrillOrgIDarr');

  let checkResult;
  if (this.formEntity.ExamType == 0) {
    checkResult = await this.checktypetask(this.formEntity.ExamType, this.formEntity.DrillOrgIDarr, item.value[0].ID);
  } else {
    checkResult = await this.checktypetask(this.formEntity.ExamType, this.formEntity.ByCheckOrgIDs, item.value[0].ID);
  }

  if (checkResult) {
    this.formEntity.PostName = item.value[0].text;
    this.formEntity.PostId = item.value[0].ID;
    this.showPosition = false;
  } else {
    return;
  }
}

这样，当 `checktypetask` 函数返回 `false` 时，就会直接跳过赋值操作。