C语言程序求具有abcd=(ab+cd)2性质的四位数。 **输入格式要求：提示信息："There are following numbers:\n" **输出格式要求："%d "（注意%d后面又两个空格） 程序运行示例如下： There are following numbers: 2025 3025 9801

#include <stdio.h>

int main() {
    printf("There are following numbers:\n");
    for (int i = 1000; i < 10000; ++i) {
        int ab = i / 100;
        int cd = i % 100;
        if ((ab + cd) * (ab + cd) == i) {
            printf("%d  ", i);
        }
    }
    return 0;
}

输出结果为：

There are following numbers:
2025  3025  9801