hostname=$(nova show $i | grep '\<name\>' | tail -n 2 | head -n 1 | awk '{print$4}')
时间: 2023-10-13 18:06:26 浏览: 48
这是一段 Bash 脚本代码,它的作用是获取 Nova 中虚拟机实例的主机名。具体解释如下:
- nova show $i:查看虚拟机实例 $i 的详细信息。
- grep '\<name\>':在虚拟机实例信息中查找包含关键词 "name" 的行。
- tail -n 2:只保留最后两行,这两行包含了虚拟机实例的名称信息。
- head -n 1:只获取这两行中的第一行,也就是我们需要的名称信息。
- awk '{print$4}':在获取到的名称信息中提取出第四个字段,也就是虚拟机实例的主机名。
综上所述,这段代码的作用是获取虚拟机实例 $i 的主机名并将其保存在变量 hostname 中。
相关问题
#!/bin/bash users=$(cut -d: -f1 /etc/passwd) for user in $users do if [[ $(getent passwd $user | cut -d: -f3) -ge 1000 ]] then if [[ $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ') == "never" ]] then echo "$user: Password never expires" else expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s) current_date=$(date +%s) if [[ $expire_date -lt $current_date ]] then echo "$(hostname -I | awk '{print $1}'),$user: Password has expired" else echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" fi fi else echo "" account_status=$(passwd -S $user | awk '{print $2}') if [[ "$account_status" == "L" ]]; then echo "$(hostname -I | awk '{print $1}'),User $user: account locked!" fi done语法问题
在第27行缺少一个 `fi` 关键字来结束第20行的 `if` 语句。同时,第24行的 `echo` 命令中,应该把逗号放在双引号内,否则会被视为两个参数。正确的脚本如下:
```
#!/bin/bash
users=$(cut -d: -f1 /etc/passwd)
for user in $users
do
if [[ $(getent passwd $user | cut -d: -f3) -ge 1000 ]]
then
if [[ $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ') == "never" ]]
then
echo "$user: Password never expires"
else
expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s)
current_date=$(date +%s)
if [[ $expire_date -lt $current_date ]]
then
echo "$(hostname -I | awk '{print $1}'), $user: Password has expired"
else
echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')"
fi
fi
else
account_status=$(passwd -S $user | awk '{print $2}')
if [[ "$account_status" == "L" ]]; then
echo "$(hostname -I | awk '{print $1}'), User $user: account locked!"
fi
fi
done
```
#!/bin/bash users=$(cut -d: -f1 /etc/passwd) for user in $users do if [[ $(getent passwd $user | cut -d: -f3) -ge 1000 ]] then if [[ $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "never" || $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "从不" ]] then echo "$user: Password never expires" else expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s) current_date=$(date +%s) if [[ $expire_date -lt $current_date ]] then echo "$(hostname -I | awk '{print $1}'), $user: Password has expired" else echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" fi fi else account_status=$(passwd -S $user | awk '{print $2}') if [[ "$account_status" == "L" ]]; then echo "$(hostname -I | awk '{print $1}'), User $user: account locked!" fi fi done帮我把这段代码的第一个if去掉
好的,这是去掉第一个if之后的代码:
```bash
#!/bin/bash
users=$(cut -d: -f1 /etc/passwd)
for user in $users
do
if [[ $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "never" || $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "从不" ]]
then
echo "$user: Password never expires"
else
expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s)
current_date=$(date +%s)
if [[ $expire_date -lt $current_date ]]
then
echo "$(hostname -I | awk '{print $1}'), $user: Password has expired"
else
echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')"
fi
fi
account_status=$(passwd -S $user | awk '{print $2}')
if [[ "$account_status" == "L" ]]; then
echo "$(hostname -I | awk '{print $1}'), User $user: account locked!"
fi
done
```
注意,去掉了第一个if语句后,需要将原代码中的第二个if移动到第一个if的位置,以保证逻辑正确。